Grant Valley School has hired a fleet of buses and vans to transport 96 students to a picnic. Each bus can seat 31 people, and e
2 answers:
Let x be the<u> number of buses</u> and y be the <u>number of vans</u> needed to transport 107 people.
1. If each bus can seat 31 people and 3 of them should be teachers, then x buses can seat (31-3)x=28x students. If each van can seat 9 people and 1 of them should be teacher, then y vans can seat (9-1)y=8y students.
2. Grant Valley School has hired a fleet of buses and vans to transport 96 students to a picnic.Thus,
28x+8y=96.
3. It will take to accommodate 107 people, including the 96 students and teachers, then the number of teachers is 107-96=11.
x buses will take 3x teachers and y vans will take y teachers,
Therefore, 3x+y=11.
4. Solve the system of equations:
Solve the first equation:
Then
Answer: 2 buses and 5 vans
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Answer:
280 people
Step-by-step explanation:
Given that 65% of people surveyed were pleased with condition of the park.
Given that those pleased were 182 people, then finding the total number of people surveyed will be;
65%= 182 people
100%= ?--------------------cross multiply
Answer:
The correct option is (A).
Step-by-step explanation:
Let <em>X</em> = number of orange milk chocolate M&M’s.
The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.
The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.
The event of an milk chocolate M&M being orange is independent of the other candies.
The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.
The expected value of a Binomial random variable is:
Compute the expected number of orange milk chocolate M&M’s in a bag of 55 candies as follows:
It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.
This proportion is not surprising.
This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.
All unusual events have a very low probability, i.e. less than 0.05.
Compute the probability of P (X ≥ 14) as follows:
The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.
This probability is quite larger than 0.05.
Thus, the correct option is (A).