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wel
2 years ago
14

Emma borrowed $300 to repair her car. the finance (interest) charge on the loan was $20, and the term on the loan was 14 days. w

hat was the apr for emma's loan? (popup calculator)
Mathematics
1 answer:
Murrr4er [49]2 years ago
7 0
Given:
loan amount = 300
finance charge = 20
term = 14 days.

To solve for APR.
<span>1. Divide the finance charge by the loan amount.
20/300 = 0.0667

2. Multiply the result by 365. 
0.0667 x 365 = 24.35

3. Divide the result by the term of the loan.
24.35/14 = 1.74 (APR in decimal format)
<span>
4. Multiply the result by 100.
1.74 x 100 = 174% APR</span></span>
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Math your class is holding elections to choose a leadership committee of 4 students. if there are 30 students in the class, how
inessss [21]
That would be 30C4  - combinations of 4 from 30.



= 30*29*28*27       
   ----------------  =  27,405  Answer 
   4 * 3 * 2 * 1
7 0
2 years ago
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
2 years ago
Han is multiplying by and gets . He says that is not a polynomial because 0.5 is not an integer. What is the error in Han’s thin
Marina86 [1]

Step-by-step explanation:

Han is multiplying10x^4 by 0.5^3 and gets 5x^7 is not a polynomial because 0.5 is not an integer. What is the error in han’s thinking explain

On multiplying 10x⁴ by 0.5x³,

10x^4\times 0.5x^3=(10\times 0.5)x^{4+3}\\\\=5x^7

A polynomial is a combination of coefficients and variables. It is made up of one or more monomial. Han says that it is not a polynomial because 0.5 is not an integer. The statement is false. After multiplication we get 5x⁷. It has a variable x and constant 5. Hence, its is a polynomial.

4 0
2 years ago
A group of 75 math students were asked whether they like algebra and whether they like geometry. A total of 45 students like alg
Yuki888 [10]

Answer:

Step-by-step explanation:

Let x be the number of students that like both algebra and geometry. Then:

1. 45-x is the number of students that like only algebra;

2. 53-x is the number of students that like only geometry.

You know that 6 students do not like any subject at all and there are 75 students in total.

If you add the number of students that like both subjects, the number of students that like only one subject and the number of students that do not like any subject, you get 75.

Therefore,

x+45-x+53-x+6=75.

Solve this equation:

104-x=75,\\\\x=104-75,\\\\x=29.

You get that:

29 students like both subjects;

45-29=16 students like only algebra;

53-29=24 students like only geometry;

24+6=30 students do not like algebra;

16+6=22 students do not like geometry.

a = 29, b = 16, c = 24, d = 30, e = 22

<h3>The correct choice is D.</h3>

5 0
2 years ago
Read 2 more answers
A researcher measures IQ and weight for a group of college students. What kind of correlation is likely to be obtained for these
Sunny_sXe [5.5K]

Answer:

Option b

Step-by-step explanation:

Given that a  researcher measures IQ and weight for a group of college students.

In general, we think that the weight has nothing to do with IQ of a person and hence not correlated.

But if we go deep, we find that after a certain weight, the person becomes lazy and inactive with a chance to have reduced IQ

Weight gain causes also health problems including less activity of both brain and body and hence there is a chance for less IQ

So we find that as weight increases iq decreases and when weight decreases, IQ increases.

Thus we can say that there is a negative correlation but not necessarily near to one.

Hence option b is right

8 0
2 years ago
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