The relative frequencies, from least to greatest, would be:
The percentage of all entries painted by Art 1 students (14.33%), the percentage of Art 2 entries that were digital (22.02%), and the percentage of clay entries done by Art 3 students (25.32%).
Explanation
The percentage of clay entries done by Art 3 students: There are 20 clay entries done by Art 3 students, out of 79 clay entries; 20/79 = 25.32%
The percentage of all entries painted by Art 1 students: There are 43 entries painted by Art 1 students out of 300 total; 43/300 = 14.33%
The percentage of Art 2 entries that are digital: There are 24 Art 2 digital entries out of 109 total Art 2 entries; 24/109 = 22.02%
We are given with
F = 1000
b = 22.50
P = 100.8
We use the formula to get the coupon rate
b = Fib
Substituting the given values
22.50 = 1000 ib
ib = 0.0255 or 2.25%
The coupon rate is 2.25%
Answer:
The number of dogs that had both Lyme disease and arthritis is 18
Step-by-step explanation:
Let x represent dogs that have both Lyme disease and arthritis
Dog with only Lyme disease = 42 - x
Dog with only arthritis = 96 - x
The sum of the 3 category should give 120
x + (42 - x) + (96 - x) = 120
Collect like terms and solve
x - x - x + 42 + 96 = 120
-x + 138 = 120
138 - 120 = x
x = 18
Dog with only Lyme disease = 42 - x = 42 - 18 = 24
Dog with only arthritis = 96 - x = 96 - 18 = 78
Therefore, the number of dogs with both Lyme disease and anthritis is 18.
If we turn this to a ratio we get 64:16 and we need ?:18.5. To easily solve this we would divide 64 by 16 and 64/16= 4 now that we know that the shoulder width is 1/4 if a persons height we can then multiply 18.5 by 4 to find the woman’s height. 18.5x4=74
So your answer is 74 inches
