Question

. Every month, there are 1000 independent TIE fighter flights, and each TIE fighter flight crashes with a probability of 0.0035. (a) What is the probability that at least 2 crashes occur in the next month

Answer 1

Answer:

$\mathbf{P (X \geq 2) = 1 - P( X \leq 1) \sum \limits ^1_{x=0} ( ^{1000}_x) (0.0035)^x (0.9965)^{1000-x}}$

Step-by-step explanation:

From the information given:

The probability that at least 2 crashes occurs in the next month can be estimated by using Poisson distribution because the sample size is large and the probability of the event p = 0.0035 is rare.

∴

Let X be the random variable that follows a Poisson  distribution

The probability that at least 2 crashes occurs in the next month is:

$\mathbf{P (X \geq 2) = 1 - P( X \leq 1) \sum \limits ^1_{x=0} ( ^{1000}_x) (0.0035)^x (0.9965)^{1000-x}}$