Answer:
ΔLK ΔJKL
Step-by-step explanation:
I'm not positive cause im still learning this
There are a total of 30 integers and 10 of these are divisible by 3 (3, 6, 9, 12, 15, 18, 21, 24, 27, and 30). So the probability of getting an integer divisible by 3 is
= 1/3. The answer is letter C.
Add the two equations and use the elimination method. The x term will "cancel out" to be able to solve for the y term.
STEP 1
−12x−5y=40
12x−11y=88
x terms "cancels out"; add y terms
-16y= 128
divide both sides by -16
y= -8
STEP 2
substitute y value into either original equation
12x−11y=88
12x - 11(-8)= 88
12x + 88= 88
subtract 88 from both sides
12x= 0
divide both sides by 12; 0 divided by any number is 0
x= 0
ANSWER: x= 0; y= -8
Hope this helps! :)
Answer:
3 - (n - 1) = 1/2(3n - 4)
Step-by-step explanation:
We want to write three minus the difference of a number and one equals one-half of the difference of three times the same number and four as an equation.
Let the number be n.
The first part is: three minus the difference of a number and one:
3 - (n - 1)
The second part is: one-half of the difference of three times the same number and four:
1/2(3n - 4)
Now, let us equate the first and second parts:
3 - (n - 1) = 1/2(3n - 4)
PS: I really do not understand the options
