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2 years ago

A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

5 0

Answer:

<h2>The area of the pitch in an acre is 1.32 acre</h2>

Step-by-step explanation:

This problem requires to test our understanding of unit conversion, and we are expected to present our answer in an acre

first, let us convert from the yard to feet

given that the dimension of the pitch is

120 yards by

53.333 yard

1 yard is 3 foot

120 yards will give x

cross multiply we have

x1= 120*3

x1= 360 feet

also the second dimension is

x2= 53.333*3

x2= 159.999

x2= 159.999 feet

the area of the pitch is

area= 159.999*360

area= 57599.64 ft^2

Note: an acre is a unit for land area (1 acre=43560 ft^2)

if 1 acre = 43560 ft^2

x acre = 57599.64 ft^2

cross multiply we have

x acre = 57599.64/43560

x acre = 1.32 acre

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It is common in many industrial areas to use a filling machine to fill boxes full of product. This occurs in the food industry a

Sphinxa [80]

Answer:

(a) P(B) = 0.008, (b) P(A∩B) = 0, (c) Yes, A and B are mutually exclusive events, (d) P(A∪B)=0.948, (e) 0.948, (f) 0.06

Step-by-step explanation:

We have three different posibilities

A: fill to specification

B: underfill

C: overfill

in probability the sum of the different events which are mutually exclusive should sum to 1, so, we should have

(a) P(B) = 1 - P(A)-P(C) = 1-0.940-0.052=0.008

(b) P(A∩B)=probability that the machine fill to specification and underfill = 0 because a machine can't fill to specification and underfill at the same time

(c) Yes, A and B are mutually exclusive events, because a machine can't fill to specification and underfill at the same time

(d) Because A and B are mutually exclusive events we should have that

P(A∪B)=P(A)+P(B)=0.940+0.008=0.948

(e) The probability that the machine does not overfill is the same that the probability that the machine fill to specification plus the probability that the machine underfill, i.e, the probability that the machine does not overfill is P(A)+P(B)=0.948, because does not overfill is equivalent either to fill to specification or to underfill.

(f) The probability that the machine either overfill or underfills is

P(C∪B)=P(C)+P(B)=0.052+0.008=0.06 because C and B are mutually exclusive events.

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2 years ago

A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20

ANEK [815]

Y = 0.213x – 352.0 <span> represents this linear model shown in the data table.
Plug in the values of x into the equation for a double check.
Let's try 1980.

</span><span>y = 0.213(1980) – 352.0
</span>y = 69.74
which is closest to the 70.1 whereas other options do not satisfy the condition.

6 0

2 years ago

Read 2 more answers

The polynomial equation x cubed minus 4 x squared + 2 x + 10 = x squared minus 5 x minus 3 has complex roots 3 plus-or-minus 2 i

Tpy6a [65]

Answer: Answer is B, -1

Step-by-step explanation:

This is the correct answer according to Edge

This should be a five star btw sorry

7 0

2 years ago

Read 2 more answers

Suppose we have a group of 10 light users and 10 heavy users. what is the probability that exactly 3 of the 20 users are hiv pos

dmitriy555 [2]

Answer: The answer is 30%.

Step-by-step explanation: Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.

We have the following four possible cases -

(i) All 3 are light users.

(ii) 1 is a light user and 2 are heavy users.

(iii) 2 are light users and 1 is a heavy user.

(iv) All 3 are heavy user.

Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

$p\\\\=\dfrac{3\times 0.45+1\times 0.45+2\times 0.55+2\times 0.45+1\times 0.55+3\times 0.55}{20}\\\\=\dfrac{6}{20}\\\\=0.3\\\\=30\%.$

Thus, the probability is 30.

4 0

2 years ago

fifteen darts have landed on the dart board shown. each dart scores 3,5, or 7 points. in how many different ways can the fifteen

lukranit [14]

Answer:

The answer is "8".

Step-by-step explanation:

Let the number are a, b, c then value is as follows:

a= 3

b= 5

c= 7

The addition of equation ⇒ a+b+c =15....................(i)

multiply by the value ⇒ 3a + 5b + 7c = 75 ...............(ii)

let b= 15-a-c which subtract from equation (ii)

equation:

⇒ 3a + 5b + 7c = 75

⇒ 3a + 5(15-a-c) + 7c = 75

⇒ 3a +75-5a-5c+7c = 75

⇒ 3a -5a-5c+7c = 75-75

⇒ -2a + 2c = 0

⇒ 2(c-a) = 0

⇒ (c-a) = 0

⇒ c=a

if we put value in between 0 to 7 from it satisfies the two equations, with c=a and b = 15 - a - c. So, the correct answer is 8.

3 0

2 years ago