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2 years ago

A student observes that for the same net force heavier objects accelerate less which statement describes the correct conclusion?

Physics

2 answers:

rodikova [14]2 years ago

4 0

Answer: A decrease in acceleration causes the mass to increase.

Explanation:

Let's rewrite this as:

"For a constant force F, we can see that heavier objects accelerate less"

Then, as the mass increases, the acceleration of the object decreases.

This is known as an inverse relationship between acceleration and mass.

By second Newton's law we have that:

F = m*a

Force equals mass times acceleration.

So if the force is constant, we can write it as:

a = F/m.

In this equation, we can see that, if the acceleration decreases and F remains constant, then the mass m must increase (because it is in the denominator)

Then the correct option is:

A decrease in acceleration causes the mass to increase.

ss7ja [257]2 years ago

3 0

Answer:

There is a negative correlation between mass and acceleration.

Explanation:

Facundo is wrong. I got this wrong thanks to Facundo!

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Two wheels can rotate freely about fixed axles through their centers. The wheels have the same mass, but one has twice the radiu

Murrr4er [49]

Answer:

The force on second wheel is twice off the force on first wheel.

Explanation:

In this case, two wheels can rotate freely about fixed axles through their centers. We know that, in rotational mechanics, the torque is given by :

$\tau=I\alpha$

Also, $\tau=Fr$

And moment of inertia is, $I=mr^2$

It implies,

$Fr=mr^2\alpha \\\\F=mr\alpha$

Here, one has twice the radius of the other. Ratio of forces will be :

$\dfrac{F_1}{F_2}=\dfrac{mr_1\alpha }{mr_2\alpha }\\\\\dfrac{F_1}{F_2}=\dfrac{r_1 }{2r_1}\\\\\dfrac{F_1}{F_2}=\dfrac{1 }{2}\\\\F_2=2F_1$

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2 years ago

A mis-hit golf ball flies straight up in the air. Exactly 4.0 seconds later it lands right next to the tee. How high up did the

Juliette [100K]

Answer:

19.6 m

Explanation:

The total motion of the golf ball lasts 4.0 seconds: since the motion is symmetrical, it takes 2.0 s for the ball to reach the highest point and then another 2.0 s to land back on the tee.

Therefore, we can just analyze the second half of the motion that lasts

t = 2.0 s

During this time, the vertical distance covered by the ball is given by the equation:

$d=ut+\frac{1}{2}gt^2$

where

u = 0 is the initial velocity (zero because the ball starts from its highest point, where the velocity is zero)

t = 2.0 s

g = 9.8 m/s^2 is the acceleration of gravity

Solving for d, we find:

$d=\frac{1}{2}(9.8)(2.0)^2=19.6 m$

So, the ball reaches a maximum height of 19.6 m.

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