Answer:
The amplitude is 2.3 m
The Wavelength is 8.6 m
The frequency is 0.16 Hz
The time period is 6.25 sec
The equation that governs the behavior is ![Y=(2.3)sin[(\frac{2\pi}{8.6} )x -(\frac{2\pi}{6.2} )t]](https://tex.z-dn.net/?f=Y%3D%282.3%29sin%5B%28%5Cfrac%7B2%5Cpi%7D%7B8.6%7D%20%29x%20-%28%5Cfrac%7B2%5Cpi%7D%7B6.2%7D%20%29t%5D)
Explanation:
The explanation is shown on the first uploaded image
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03
Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:

where

is the coefficient of friction, while N is the normal force. So we have:

since we know that F=300 N and

, we can find N, the magnitude of the normal force:

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is

due to the presence of the oil. Therefore, we have:
Elastic potential = 1/2 x constant x square of compression lenght
So it's 360 N/m
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