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jonny [76]
2 years ago
8

Classify these compounds as acid, base, salt, or other.? 1. ch3oh 3. hno3 5. nabr

Chemistry
2 answers:
Nesterboy [21]2 years ago
7 0

Explanation:

Acids are the species which upon dissociation in water gives hydrogen ions (H^{+}).

For example, HNO_{3} is acidic in nature because upon dissociation it releases H^{+} ions as follows.

            HNO_{3} \rightarrow H^{+} + NO^{-}_{3}

Whereas bases are the species which upon dissociation in water gives hydroxide ions (OH^{-}).

For example, NaOH is basic in nature as it releases OH^{-} ions.

Salts are the substances formed by combination of two or more different oppositely charged ions.

For example, NaCl is a salt.

Therefore, we classify the given compounds as acid, base, salt, or other as follows.

  • CH_{3}OH - Other
  • HNO_{3} - Acid
  • NaBr - Salt

ELEN [110]2 years ago
5 0
<span> </span><span>1. Alcohol(other) 
3. Acid 
5. Salt 

</span>
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(a) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm3. (b) A student needs 15.0 g of ethanol fo
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<u>Answer:</u>

<u>For a:</u> The density of the sample of copper is 8.96g/cm^3

<u>For b:</u> The volume of ethanol needed is 19.0 mL

<u>For c:</u> The mass of mercury is 340. grams

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}      ......(1)

  • <u>For a:</u>

Mass of copper = 374.5 g

Volume of copper = 41.8cm^3

Putting values in equation 1, we get:

\text{Density of copper}=\frac{374.5g}{41.8cm^3}\\\\\text{Density of copper}=8.96g/cm^3

Hence, the density of the sample of copper is 8.96g/cm^3

  • <u>For b:</u>

Mass of ethanol = 15.0 g

Density of ethanol = 0.789 g/mL

Putting values in equation 1, we get:

0.789g/mL=\frac{15.0g}{\text{Volume of ethanol}}\\\\\text{Volume of ethanol}=\frac{15.0g}{0.789g/mL}=19.0mL

Hence, the volume of ethanol needed is 19.0 mL

  • <u>For c:</u>

Volume of mercury = 25.0 mL

Density of mercury = 13.6 g/mL

Putting values in equation 1, we get:

13.6g/mL=\frac{\text{Mass of mercury}}{25.0mL}\\\\\text{Mass of mercury}=(13.6g/mL\times 25.0mL)=340.g

Hence, the mass of mercury is 340. grams

5 0
2 years ago
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