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Deffense [45]
2 years ago
15

What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of soluti

on?What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of solution?0.224 M4.46 × 103 M4.46 M2.24 × 10-4 M
Chemistry
1 answer:
puteri [66]2 years ago
7 0

Answer: The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute =\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10.0g}{162.2g/mol}=0.0616moles

{V_s} = volume of solution in ml = 275 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.0616\times 1000}{275ml}=0.224mole/L

Therefore, the concentration of solution will be 0.224 M

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The concentration of ozone in a sample of air that has a partial pressure of O3 of 0.33 torr and a total pressure of air of 695
Goryan [66]

Answer:

0.047 %

Explanation:

Step 1: Given data

  • Partial pressure of ozone (pO₃): 0.33 torr
  • Total pressure of air (P): 695 torr

Step 2: Calculate the %v/v of ozone in the air

Air is a mixture of gases. We can find the %v/v of ozone (a component) in the air (mixture) using the following expression.

<em>%v/v = pO₃/P × 100%</em>

%v/v = 0.33 torr/695 torr × 100%

%v/v = 0.047 %

8 0
2 years ago
The compound AX2 decomposes according to the equation, 2 AX2(g) =&gt; 2 AX(g) + X2(g). In one experiment, AX2 was measured at va
Karolina [17]

Answer:

0.0011 mol/L.s

Explanation:

The average rate of disappearing of the reagent is the variation of the concentration of it divided by the time that this variation is being measured. The reaction rate, is proportional to the coefficient of the substance, so, for a generic reaction:

aA + bB --> cC + dD

rate = -(1/a)Δ[A]/Δt = -(1/b)Δ[B]/Δt = (1/c)Δ[C]/Δdt = (1/d)Δ[D]/dt

The minus sign is because of the reagent is desapering, so:

rate = -(1/2)*(0.0209 - 0.0300)/(10 - 6)

rate = 0.0011 mol/L.s

8 0
2 years ago
Why carbon dioxide in the atmosphere appears to be increasing
Mumz [18]

Answer:

Explanation:

Burning fossil fuels releases the carbon dioxide stored millions of years ago. ... The concentration of carbon dioxide in the atmosphere has increased more in the northern hemisphere where more fossil fuel burning occurs. Since the Industrial Revolution the concentration globally has increased by about 40 % .

4 0
2 years ago
Read 2 more answers
How many moles of Helium gas are in a balloon with a volume of 6.452 L at 99.7 kPa
Taya2010 [7]

Answer:

n = 0.26 mol.

Explanation:

Given,

Pressure, P = 99.7 kPa = 1 atm

where 101.325 kPa  = 1 atm

            P = 0.984 atm

Temperature, T = 297 K

Volume = 6.452 L

Now, using ideal gas equation

PV = n RT

0.984 x 6.452 = n x 0.08206 x 297

n = 0.26 mol.

8 0
2 years ago
A 0.821 gram sample of pure NH F was treated with 25.0 mL of 1.00 M NaOH
Olegator [25]

Answer:

0.0222 mole of NaOH is needed to react with NH4F

Explanation:

NH4F + NaOH --> NaF + NH3 + H2O

Data given

Mass of NH4F =0.821g, Concentration of NaOH= 1M, volume of NaoH =25ml

But mole = (CV)/1000

given mole of NaoH = (1 * 25)/1000 = 0.025moles of NaOH used

Molar mass of NH4F = 37g/mol

mole of NH4F used 0.821 / 37 = 0.0222 mole NH4F

Determine the excess and limiting reactant,

NaOH is in excess

0.025 - 0.0222 = 0.0028 mole NaOH excess

0.0222 mole of NaOH is required to react with NH4F

8 0
2 years ago
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