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pogonyaev
2 years ago
9

Which of the following statements is a true statement concerning a reaction that has reached a state of equilibrium?

Chemistry
1 answer:
Inga [223]2 years ago
8 0

Answer: A system has reached equilibrium when the concentrations of reactants and products remain constant.

Explanation:

The reactions which do not go on completion and in which the reactant forms product and the products goes back to the reactants simultaneously are known as equilibrium reactions.

The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time, that is the concentration remains constant.

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An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i
katovenus [111]
The  answer is

<span>The density (D) is quotient of mass (m) and volume (V):
</span>D= \frac{m}{V}
The unit is g/cm³

It is given:
m = 1.62 kg = 1620 g
V = 205 mL = 205 cm³
D = ?

Thus:
D= \frac{m}{V} = \frac{1620g}{205cm ^{3} } = 7.90 g/cm ^{3}

The density of the goblet is 7.90 g/cm³.
5 0
2 years ago
A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5×10−9m, and 1.00 ml
Elis [28]

The concentration of the drug stock solution is 1.5*10^-9 M i.e. 1.5 * 10^-9 moles of the drug per Liter of the solution

Therefore, the number of moles present in 1 ml i.e. 1*10^-3 L of the solution would be =  1 *10^-3 L * 1.5 * 10^-9 moles/1 L = 1.5 * 10^-12 moles

1 mole of the drug will contain 6.023*10^23 drug molecules

Therefore, 1.5*10^-12 moles of the drug will correspond to :

    1.5 * 10^-12 moles * 6.023*10^23 molecules/1 mole = 9.035 * 10^11 molecules

The number of cancer cells = 2.0 * 10^5

Hence the ratio = drug molecules/cancer cells

                          = 9.035 *10^11/2.0 *10^5

                          = 4.5 * 10^6

8 0
2 years ago
Read 2 more answers
If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m
lara [203]

Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

A = π (100)^{2} / 4;  

We can take π as 3.14 and we get;

A = 3.14 X (100)^{2} / 4  

Soving we get;

A =  7850 μm^{2}  

Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μm^{2}  but;

here 1 μm^{2} = 7850 μm^{2} dye molecules.

Therefore, 10 fluorescent molecules will need;  

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.

6 0
2 years ago
in a candy factory, the nutty chocolate bars contain 22.0% by mass pecans. If 5.0 kg of pecans were used for candy last Tuesday,
zysi [14]
22.0 is the same as saying that in 100 grams of a chocolate bar, there are 22.0 grams of pecans. or to make it easier because of this problem- 100 Kilograms of a chocolate bar, there is 22.0 Kg of pecans. we can use this as a conversion factor (what is used to convert a value to another value. 

conversion factor---> 22.0 kg of pecan= 100 kg of chocolate bar
Note: remember this, what you are converting from goes in the denominator, what you converting to goes in the numerator. 

5.0 Kg of pecan (100 Kg of chocolate bar/ 22.0 Kg of pecan)= 23 Kg of chocolate bar


7 0
2 years ago
Four different solutions (I, II, III, and IV) are labeled on the pH scale below. A p H scale is shown, fading from red at the le
andreyandreev [35.5K]

Answer: It has the highest number of hydroxide ions

Explanation: I took the review

6 0
2 years ago
Read 2 more answers
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