In order to calculate the distance between two alleles/genes that are found in the same chromosome, we need to know how often crossing-over happened (recombination frequency). We know from the text that white eyes were linked to miniature wings and that wild type eyes were linked to wild type wings, so any phenotype that's contrary to these parent combinations are a result of crossing-over. We know then that 230 flies + 240 flies were a result of such recombination. To calculate the recombination frequency we only need to divide these flies (total of recombinant flies) by the total of flies in the offspring and turn it into percentage.

=0.47
0.47*100%=47%
47 map units is the distance between the genes <span>for eye color and wing length.</span>
1) D because even if you rip all them out, the seeds of the plant are still in the ground
2) D because of the current, short-legged birds might get swept away
3) D because all of the other options would most likely not enforced.
They will shrink , that is your answer.
1. Rhythm generators (SA node)
2. Conductive cells (node cells)
3. Contractile cells (myocardial cells)
It would be A
First is: DNA > mRNA (messenger RNA) > tRNA (transfer RNA) > protein