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bearhunter [10]
2 years ago
6

What can you do to manually exclude an individual from a recipient list?

Computers and Technology
1 answer:
Marianna [84]2 years ago
5 0

Answer:

Remove the check mark next to the person in Mail Merge Recipients

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Terry came into work and turned on his computer. During the boot process, the computer shut down. When he tried again, the compu
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SATA Cable

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SATA (Serial Advanced Technology Attachment) Cable is a connection made between Computer hard drives and the motherboard. When a computer gives an error on startup that OS not found, there's a possibility that the drive containing the OS is not well connected to the motherboard. Making sure it is well connected to the motherboard will possibly fix the issue.

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2 years ago
EVERYONE LISTEN!!!! PLEASE COPY THIS MESSAGE AND RESEND!!!!
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Ok we will do it for you cause they are very mean
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2 years ago
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How many bits would be needed to count all of the students in class today? There are 5 children in the class.
zavuch27 [327]

Answer:

You would need 8 bits.

Explanation:

If your refer back to the binary system, the exponent 2^3 would equal 8, and since there are only 5 children, this would be more reasonable. It's better to have a little bits left over than too many. Hope this helps!

4 0
2 years ago
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For f
julia-pushkina [17]

Complete Question:

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

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a) 51.2 msec.  b) 5.12 msec

Explanation:

If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

  • Tw = K*512* bit time

The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

a) BW  = 1 Mbps = 10⁶ bps

⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

b) BW = 10 Mbps = 10⁷ bps

⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec

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2 years ago
When seeking information on the internet about a variety of subjects the most useful place to look would be?
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Well brainly.com of course! Welcome.

For your answer, i would go with: Websites with primary source information that is verifiable and has a good reputation.
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2 years ago
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