Melissa worked to earn $20.00. Alan worked for $12.00 hours. If she earns $2.00 per hour, how many hours did Melissa work?

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Ede4ka [16]

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

Step-by-step explanation:

We need to describes Catron’s error?

The steps are:

Step 1: (Negative 9) (2 + two-fifths)

Step 2: (Negative 9) (Negative 2) + (negative 9) (two-fifths)

Step 3: Negative 18 + (negative 9) (two-fifths)

Step 4: (negative 27) (two-fifths)

Solution: Negative StartFraction 54 over 5 EndFraction = Negative 10 and four-fifths

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

<u>Solving </u>

Solving the equation by removing the error:

Step 1: (Negative 9) (2 + two-fifths)

taking LCM of 2 and two-fifths (2/5)

Step 2: (Negative 9) (twelve-fifths)

Step 3: (Negative 9*twelve)-fifths

Step 4: Negative one hundred and eight- fifths

Solution: Negative StartFraction -108 over 5 EndFraction = Negative one hundred and eight- fifths

Keywords: Solving Expressions

Learn more about Solving Expressions at:

#learnwithBrainly

5 0

2 years ago

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A taxi charges a flat rate of $3.00, plus an additional $0.50 per mile. Carl will only take the taxi home if the cost is under $

Ahat [919]

Answer: Take the bus to save money

Step-by-step explanation:

you plug x for 15, the inequality would be ($0.50 * 15) + $3 < $10. We need a less than sign (<) because Carl says the price has to be under and not equal to.

$7.5 + $3 < $10. After you do simple math and add, you will know that Carl is short of money by 50 cents.

Hope this helps :)

6 0

2 years ago

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Find the cube roots of 27(cos 330Á + i sin 330Á). Please help c:

Mashcka [7]

Use formula
$e^{ix}=\cos{x}+\sin{x}$

$\sqrt[3]{27(\cos{330^o}+i\sin{330^o})} 
\\\sqrt[3]{27e^{i330^o} }
\\ \sqrt[3]{27} \sqrt[3]{e^{i330^o}} 
\\ \sqrt[3]{3^3} \sqrt[3]{e^{i110^o\times 3}} 
\\ \sqrt[3]{3^3} \sqrt[3]{(e^{i110^o})^ 3}} 
\\ 3e^{i110^o}
\\3(\cos{110^o}+i\sin{110^o})$

Since $330^o=360^o+330^o=690^o
$ and $330^o=2\times 360^o+330^o=1050^o$ there are two more solutions:
1. $3(\cos{230^o}+i\sin{230^o})$
2. $3(\cos{350^o}+i\sin{350^o})$

4 0

2 years ago

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The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions (BLS website, January 2014). Suppose a s

andrezito [222]

Answer:

a) Null hypothesis: $p \leq 0.113$

Alternative hypothesis: $p > 0.113$

b) $z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074$

The p value for this case would be given by:

$p_v =P(z>1.074)=0.141$

c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

Step-by-step explanation:

Information given

n=400 represent the random sample taken

X=52 represent the workers belonged to unions

$\hat p=\frac{52}{400}=0.13$ estimated proportion of workers belonged to unions

$p_o=0.113$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v$ represent the p value

Part a

We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.113$

Alternative hypothesis: $p > 0.113$

Part b

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074$

The p value for this case would be given by:

$p_v =P(z>1.074)=0.141$

Part c

For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

8 0

2 years ago

At right is the tunnel entrance that runs through

JulsSmile [24]

Answer:

My buddy what's popping??

Step-by-step explanation:

Those coming from the Pest end had to walk round the Castle Hill on the Buda side to be able to proceed northwards. On 10 February 1853, four years after the completion of the Chain Bridge, the building of a tunnel leading through the hill was started to the plans of Adam Clark. On 6 March 1856, the tunnel was opened for foot traffic, and on 30 April 1857 also for motor traffic. Being 350 meters in length, it leads through under the Buda Castle to the other side of the hill. Its length is approximately identical to that of the Chain Bridge, prompting anecdotes according to which the tunnel has only been built so that in rainy weather, the Chain Bridge can be shoved in and be protected from wet conditions. The entry of the tunnel at its Chain Bridge end was also fittingly designed in classicist style.

8 0

2 years ago