Therefore, Wendy's genotype must be bb and her father's must be Bb.
The genotype is your total heritable hereditary character; it is your one of a kind genome that would be uncovered by individual genome sequencing. In any case, the word genotype can likewise allude just to a specific quality or set of qualities conveyed by a person. For instance, in the event that you convey a change that is connected to diabetes, you may allude to your genotype just as for this transformation without thought of the various quality variations that you may convey.
Frogs have their way of avoiding the predators like camouflage, squirting the poisonous liquid out of their system and through their vestigial thumbs. This organ helps them by avoiding predation by stealth which makes them quiet and silent in moving so that predators won't notice them readily.
4^3 = 64
There are 64 ways to arrange the four bases (Adenine, Thymine, Cytosine, and Guanine) into triplets (include repeats of bases as well, for e.g. AAT).
Just in case you are confused by my use of Thymine above, one thing to note is that Thymine will be replaced with Uracil in RNA.
Hope this helps! :)
The correct answer is: It enters the citric acid cycle and associates with a 4-carbon molecule (OXALOACETATE), forming citric acid, and then through redox reactions regenerates the 4-carbon molecule.
The citric acid cycle is a cyclic process (part of the cellular respiration) where acetyl CoA is modified in the mitochondria to produce high-energy intermediate molecules for the oxidative phosphorilation (production of ATP).
Answer:
25%
Explanation:
The possible genotypes and phenotypes are:
- EE or Ee: thick eyebrows
- ee: thin eyebrows
- FF or Ff: free earlobes
- ff: attached earlobes
Tom and Jessica have thick eyebrows and free earlobes. Tom's mother has attached earlobes, so Tom must have inherited an <em>f</em> allele from her, and because he has free earlobes he must be heterozygous<em> Ff. </em>We assume Jessica is homozygous for free earlobes <em>FF</em>.
Tom's mother and Jessica's father have thin eyebrows, so they are both <em>ee</em> and therefore both Tom and Jessica must be heterozygous <em>Ee</em>.
From the above information, Tom has the genotype EeFf and Jessica is EeFF. If you do a Punnett Square of this cross, you'll get that the probability of having a child with free earlobes and thin eyebrows (eeF_) is 25%.
