Question

Boy Scout Troop 2 went backpacking in the Sierras. The scouts hiked 5 1/2 hours each day for 4 days. If their average speed was 1 3/4 mph, how far did the yhike altogether?

Answer 1

Given :

Time they traveled in a day , $t=5\dfrac{1}{2}=\dfrac{11}{2}\ hours$ .

Average speed , $s=1\dfrac{3}{4}=\dfrac{7}{4}\ mph$ .

To Find :

How far did they hike altogether in 4 days .

Solution :

We know , distance covered is given by :

$d=s\times t \\\\d=\dfrac{7}{4} \times \dfrac{11}{2}\ miles\\\\d=\dfrac{77}{8}\ miles$

So , distance covered in 4 days is :

$D=\dfrac{77}{8}\times 4\ miles\\\\D=38.5\ miles$

Therefore , distance they hike in 4 days is 38.5 miles .

Hence , this is the required solution .