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stepladder [879]
2 years ago
3

Russell runs 9/10 of a mile in five minutes at this rate how many miles can he run in one minute

Mathematics
1 answer:
yaroslaw [1]2 years ago
5 0

Answer:

0.18 miles per min.

Step-by-step explanation:

He runs 9/10 of a mile in five minutes, which means 0.9/1 miles in five minutes.

You then need to divide 0.9 by 5 and get 0.18 which is the answer.

Guest
1 year ago
ur a goat thx man
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On a Friday evening a pizza shop had orders for 4 pepperoni, 97, and 335 cheese pizzas. If the 4 cooks each made an equal number
aksik [14]
Add the order of pizzas together and divide by four.  Round your answer.
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2 years ago
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The price of a train ticket consists of an initial fee plus a constant fee per stop.
murzikaleks [220]

Answer:

Initial Fee is $2.

Step-by-step explanation:

Given:

Stops  Price (dollars)

3         6.50

7         12.50

11         18.50

Also Given:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

So let the Cost of initial fee be 'x'.

Also Let the Cost of Constant fee be 'y'.

Now Equation can framed as;

Price (P) = x + (y\times \textrm{Number of Stops})

Now According to table;

Number of stops = 3

Price = 6.50

So equation can be framed as;

x+3y =6.50 \ \ \ \ equation \ 1

Also According to table;

Number of stops = 7

Price = 12.50

So equation can be framed as;

x+7y =12.50 \ \ \ \ equation \ 2

Now Subtracting equation 1 from equation 2 we get;

(x+7y)-(x+3y) =12.50-6.50\\\\x+7y-x-3y=6\\\\4y =6\\\\y= \frac{6}{4}=\$1.5

Substituting the value of y in equation 1 we get;

x+3\times1.5=6.50\\\\x+4.5=6.50\\\\x =6.50-4.5 = \$2

Hence Initial Fee is $2.

8 0
2 years ago
Read 2 more answers
A runner completes a 400-m race in 43.9 s. In a 100-m race, he finishes in 10.4 s. In which race was his speed faster?
Sveta_85 [38]

Answer:

100m race

Step-by-step explanation:

because 10.4 x 4 because 100m and 400m right 10.4x4=41.6 and 43.9 so obviously the 100m race is faster.

5 0
2 years ago
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Which statements are true? Check all that apply. The equation |–x – 4| = 8 will have two solutions. The equation 3.4|0.5x – 42.1
NeX [460]

Answer:

1. The equation |-x -4| = 8 will have two solutions. (True)

5. The equation |0.5x – 0.75| + 4.6 = 0.25 will have no solutions. (True)

Step-by-step explanation:

1. The equation |-x -4| = 8 will have two solutions. (True)

|-x - 4| = 8

-x -4 = ±8

-x -4 = 8 and -x -4 = -8

-x = 8 + 4 and -x = -8 + 4

-x = 12 and -x = -4

x = -12 and x = 4

Therefore, it has two solutions x ∈ {-12, 4}

2. The equation 3.4|0.5x - 42.1| = -20.6 will have one solution. (False)

Since the right side of the equation has a negative value therefore, according to rules of absolute value equations, it has no solution.

3. The equation |1/2x - 3/4| = 0 will have no solutions. (False)

|(1/2)x - 3/4| = 0

(1/2)x - 3/4 = ±0

Since ±0 is the same

(1/2)x = 3/4

x = 2*3/4

x = 3/2

Therefore, it has one solution x = 3/2

4. The equation |2x – 10| = –20 will have two solutions. (False)

Since the right side of the equation has a negative value therefore, according to rules of absolute value equations, it has no solution.

5. The equation |0.5x – 0.75| + 4.6 = 0.25 will have no solutions. (True)

|0.5x – 0.75| + 4.6 = 0.25

|0.5x – 0.75| = 0.25 - 4.6

|0.5x – 0.75| = -4.35

Since the right side of the equation has a negative value therefore, according to rules of absolute value equations, it has no solution.

6. The equation |(1/8)x - 1| = 5 will have infinitely many solutions. (False)

|(1/8)x - 1| = 5

(1/8)x - 1 = ±5

(1/8)x - 1 = 5 and (1/8)x - 1 = -5

(1/8)x = 5 + 1 and (1/8)x = -5 + 1

(1/8)x = 6 and (1/8)x = -4

x = 6*8 and x = -4*8

x = 48 and x = -32

Therefore, it has two solutions x ∈ {48, -32}

4 0
2 years ago
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A uniform distribution is defined over the interval from 6 to 10.
zhuklara [117]

Answer:

Refer below

Step-by-step explanation:

a) a and b are the lower and higher values of the interval for which uniform distribution is defined.

Here a= 6 and b =10

b) Mean of the uniform distribution= (a+b)/2 = (6+10)/2 =8

Or int x (1/4) dx = x^2/8 = 8

c) Variance of the uniform distribution = (b^2-a^2)/12 = (100-64)/12

= 36/12 =3

Std dev = sq rt of 3 = 1.732

d) To find total area

PDF of the distribution = 1/(b-a) = 1/4, 6<x<10

Area = \int 6 to 10 of 1/4 dx

= x/4

Subtitute limits

= (10-6)/4 =1

So total area = 1

d)P(X>7) = int 7 to 10 of 1/4 dx = 3/4

e) P(7<x<9) = Int 7 to 9 of 1/4 dx = 2/4 = 1/2


8 0
2 years ago
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