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nexus9112 [7]
2 years ago
7

the scale from a square exercise mat in a gymnastic arena to a scale copy of the exercise mat is 8 m for every 2 in. The actual

area of the exercise mat is 144m2. What are the dimensions of the mat on the scale copy?
Mathematics
1 answer:
m_a_m_a [10]2 years ago
7 0

Answer: 18 and 36

Step-by-step explanation:

The scale is 8m for every 2 in and the actual area is 144m2 so we need to covert that into inches. You divide 144 by 8 which = 18 and then multiply 18 x 2 which is equal to 36.

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Walt received a package that is 2 1/3 inches long, 6 3/4 inches high, and 8 1/2 inches wide. What is the surface area of the pac
grin007 [14]
Add whole numbers: 2 + 6 + 8 = 16
Add fractions:

= 1/3 + 3/4 + 1/2

= (8 + 18 + 12) ÷ 24

= 38/24 or 1 14/24 or simplified to 1 7/12

Total surface area = 16 + 1 7/12 or 17 7/12


5 0
2 years ago
Read 2 more answers
A jar contains 27 marbles. There are 4 blue marbles and the rest are red. If a marble is chosen at random, what is the likelihoo
ikadub [295]

Answer:

23/27

Step-by-step explanation:

27-4=23

8 0
2 years ago
Rita makes and sells necklaces. The materials to make each necklace cost $2.75. Last week she made 8 necklaces and wants to make
Tresset [83]

Answer:

The error she made was that she was adding x and 2.75. She should subtract 2.75 from x.

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Step-by-step explanation:

The error she made was that she was adding x and 2.75.

She should write the equation as 8 (x - 2.75) = 78; as she spends $2.75 to make a necklace.

By using the correct equation: 8 (x - 2.75) = 78

=> 8x - 22 = 78

=> 8x = 78 + 22

=> 8x = 100

=> x = 100/8

=> x = 12.5

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Hope this helps you.

3 0
2 years ago
the richmond park gamekeeper wanted to know how many deer were in the park . he caught 90 of them and put a small tag round a ho
Alenkasestr [34]

Answer:

a. Since 10 out of 70 had a tag we can write the ratio 10:70. We need to solve for x in 90:x. x = 630 so the answer is 630.

b. An assumption he could have made is that the number of deer that had a tag and the total amount of deer were directly proportional.

5 0
2 years ago
At a rally attended by 520 people, 30% were fantes, 25% were ewes, 15% were nzemas, 20% were gas and the rest were gonjas. How m
mariarad [96]

Answer:

No. of gonjas = 52

No. of more nzemas than fantes = 78

Step-by-step explanation:

Total no. of people = 520

No. of fantes = \frac{30}{100} × 520

No. of fantes = 156

No. of ewes = \frac{25}{100} × 520 = 130

No. of nzemas = \frac{15}{100} × 520 = 78

No. of gas = \frac{20}{100} × 520 = 104

No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52

No. of fantes = 156

No. of nzemas = 78

No. of more nzemas than fantes = 156 - 78 = 78

Pie chart of the following problem is shown below.

5 0
2 years ago
Read 2 more answers
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