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ycow [4]
2 years ago
4

Keys Per Minute recently hired Anne Bradford as a data entry clerk.Her starting rate of pay is $7.50 per hour and will increase

to $8.00 per hour after 90 days. If her standard work week is 32 hours, what will her straight-time pay be 4 months from now ?
Mathematics
1 answer:
BARSIC [14]2 years ago
8 0

Answer:

<h2> $3904</h2>

Step-by-step explanation:

From the question,  since it will take 90 days that is 3 months for her hourly pay to increase to $8 per hour

we proceed to calculate her pay for the first 3 months

she works a total of 32 hours in a week

hence for three months, she would work 32*4*3= 384hours

therefore her pay for three months is= 7.5*384= $2880

Now the remaining one month her pay rate has been increased to $8 per hour

the number of hours in one month is 32*4= 128 hours

her pay would be 128*8= $1024

Her straight time pay for 4months is $2880+$1024 = $3904

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If 20a-16=12(3-a), then a=?<br><br>a)5/8<br>b)13/8<br>c)21/16<br>d)5/2​
lorasvet [3.4K]

ANSWER: B. 13/8

STEP BY STEP THING:

20a−16=12(3−a)

20a−16=−12a+36

32a−16=36

32a=52

32a/32 = 52/32

a = 13/8

5 0
2 years ago
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The volleyball team at West View High School is comparing T-shirt companies where they can purchase their practice shirts. The t
mina [271]
10.5x = 7.5x + 30
10.5x - 7.5x = 30
3x = 30
x = 30/3
x = 10

10.5(10) = 105
7.5(10) + 30 = 75 + 30 = 105

they need to purchase 10 t-shirts from each company for a total of $105 for each company
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2 years ago
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Which statement describes the graph of this polynomial function?
mixer [17]

we have

f(x)=x^5 - 6x^4 + 9x^3

using a graphing tool

see the attached figure

The graph crosses the x axis at x=0 and touches the x axis at x=3.

therefore

<u>the answer is the option</u>

The graph crosses the x axis at x=0 and touches the x axis at x=3.

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2 years ago
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In each represent the common form of each argument using letters to stand for component sentences, and fill in the blanks so tha
arlik [135]

Answer:

a

           a \to b

         \neg b

         \neg a

b

If  <u>all prime numbers are odd,</u> then <u>2 is  odd</u>.

2 is not odd.

Therefore, it is not the case that all prime numbers are odd.

Step-by-step explanation:

Considering part A

 The  first sentence is  

If all computer programs contain errors, then this program contains an error.

   The second sentence is

This program does not contain an error.

     The third  sentence is

Therefore, it is not the case that all computer programs contain errors.

Now we will use  a and  b  as the letter to denote the component sentences and   \neg a  and \neg b when the component sentences is not the case

So  a =  If all computer programs contain errors

and  

     b =  this program contains an error.

Generally then is represented as \to

Hence the first sentence is denoted as  

         a \to b

The  second sentence is represented as

            \neg b

The  third sentence is represented as

           \neg a

So part a can be represented as

      a \to b

         \neg b

         \neg a

Considering part B

Here the objective is to fill in the blank spaces so that the logic of the sentence in part b is as that in part a

    Now comparing the second statement  a and  b

                "This program does not contain an error" = "2 is not odd" = \neg b

Hence      "this program contains an error." =  "2 is  odd" =  b

     Now comparing the third  statement  a and  b

Therefore, it is not the case that all computer programs contain errors.  

                                                =

     Therefore, it is not the case that all prime numbers are odd  

                                                =

                                                \neg a

Hence

If all computer programs contain errors, = if all prime numbers are odd.= a                

             

             

3 0
2 years ago
Question
monitta

Answer:

927,154\ people

Step-by-step explanation:

we have a exponential function of the form

y=a(b^x)

where

y is the population of San Francisco

x is the number of years

a is the initial population

b is the base

r is the rate of grown

b=(1+r)

In this problem we have

r=1.26\%=1.26/100=0.0126

b=1+0.0126=1.0126

ordered pair (6, 870,887)

substitute in the exponential function y=a(b^x)

870,887=a(1.0126^6)

Solve for a

a=870,887/(1.0126^6)

a=807,857\ people

so

The exponential function is equal to

y=807,857(1.0126^x)

In 5 more years the number of years will be equal to

6+5=11 years

For x=11 years

substitute the value of x in the exponential function and solve for y

y=807,857(1.0126^{11})

y=927,154\ people

6 0
2 years ago
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