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Mrac [35]
2 years ago
3

The distribution of monthly rent for one-bedroom apartments in a city is approximately normal with mean $936 and standard deviat

ion $61. A graduate student is looking for a one-bedroom apartment and wants to pay no more than $800 in monthly rent. Of the following, which is the best estimate of the percent of one-bedroom apartments in the city with a monthly rent of at most $800 ?
(A) 1.3%
(B) 2.5%
(C) 50%
(D) 95%
(E) 97.5%
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
7 0

Answer: (A) 1.3%

Step-by-step explanation:

Given: The monthly rent for one-bedroom apartments in a city is approximately normal with mean $936 and standard deviation $61.

i.e. \mu=936\ \ \ , \sigma=61

Let X denotes the monthly rent for one-bedroom apartments.

Required probability = P(X\leq800)=P(\dfrac{X-\mu}{\sigma}\leq\dfrac{800-936}{61})

=P(Z\leq\dfrac{-136}{61})\ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=P(Z\leq-2.23)\\\\=1-P(Z\leq 2.23)\ \ \ [P(Z

Hence, the correct option is (A) 1.3%

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Three times the sum of half Carlita's age and 3 is at least 12. What values represent Carlita's possible age?
cestrela7 [59]

Answer:

at least 6

Step-by-step explanation:

3(.5x+3)>12

1.5x+9>12

1.5>9

x>6

5 0
2 years ago
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Rachel loves to bake cookies, but she has an old oven that has trouble maintaining a constant temperature. Assume the acceptable
denis-greek [22]

Answer:

3.00

Step-by-step explanation:

USL = 350+18 = 368

z = (USL-Mean)/6*σ = (368-350)/6*σ

σ = 3/0.9999966 = 3.00 (approx)

7 0
2 years ago
The isosceles triangle has a base that measures 14 units. The value of y, the length of each leg, must be equal to 7. between 7
Dvinal [7]
1.The isosceles triangle has sides of length 14, y, y

2. According to the "triangle inequality" :

y+y>14
2y>14
y>14/2=7

(y is greater than 7)

3. Remark, check the figures:

the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2

In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.

4 0
2 years ago
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Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat
Ksenya-84 [330]

Answer:

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

5 0
1 year ago
Jason hires groundskeepers. They work an average of 60 hours per month. If seven groundskeepers are hired at $12/hour, what is t
Kamila [148]
Multiply the cost per hour by 60 to find the cost for a groundskeeper
cost = 12 × 60
cost = 720
The cost for each groundskeeper is $720

Find the cost for seven groundkeepers
Multiply cost for each groundskeeper by 7
cost = 720 × 7
cost = 5,040

The monthly labor cost for seven groundskeepers is $5,040
5 0
2 years ago
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