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Alla [95]
2 years ago
15

Oil is leaking from a broken pipeline into a lake. In the first 10 minutes, 400 gallons of oil have leaked, covering 8000 square

feet of the surface of the lake.
Select all options that describe the rate at which the oil is leaking (or covering the surface of the lake).\
Mathematics
1 answer:
serg [7]2 years ago
7 0

Answer:

800 square feet per minute

Step-by-step explanation:

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More than $70 billion is spent each year in the drive-thru lanes of America’s fast-food restaurants. Having quick, accurate, and
artcher [175]

Answer:

a) There is no significant difference between restaurants with and without order-confirmation boards

b) -12.5 ± 3.604 or C.1.E (-16.10, -8.90)

Step-by-step explanation:

answers are in the attachment below

8 0
2 years ago
There are 6 blades on each windmill how many total blades are on 7 vwindmills? use fives facts to solves
aliina [53]
6 times 7 = 42      hope helped

8 0
2 years ago
Multiplying StartFraction 3 Over StartRoot 17 EndRoot minus StartRoot 2 EndRoot EndFraction by which fraction will produce an eq
ziro4ka [17]

The fraction which produce an equivalent fraction with a rational denominator is \left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)

Explanation:

The equation is \frac{3}{\sqrt{17}-\sqrt{2}}

To find the rational denominator, let us take conjugate of the denominator and multiply the conjugate with both numerator and denominator.

Rewriting the equation, we have,

\frac{3}{\sqrt{17}-\sqrt{2}}\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)

Multiplying, we get,

\frac{3(\sqrt{17}+\sqrt{2})}{(\sqrt{17})^{2}-(\sqrt{2})^{2}}

Simplifying the denominator, we get,

\frac{3(\sqrt{17}+\sqrt{2})}{17-2}

Subtracting, the values of denominator,

\frac{3(\sqrt{17}+\sqrt{2})}{15}

Dividing the numerator and denominator,

\frac{\sqrt{17}+\sqrt{2}}{5}

Hence, the denominator has become a rational denominator.

Thus, the fraction which produce an equivalent fraction with a rational denominator is \left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)

6 0
2 years ago
Read 2 more answers
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
2 years ago
If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three option
meriva

Answer:

Option (1)

Step-by-step explanation:

In the figure attached,

BC is the angle bisector of angle ACD.

To prove ΔABC and ΔDBC congruent by SAS property we require two sides and the angle between these sides to be congruent.

Since BC ≅ BC [Reflexive property]

∠ABC ≅ ∠CBD ≅ 125°

And sides AB ≅ BD

Both the triangles will be congruent.

Therefore, additional information required to prove ΔABC ≅ ΔDBC have been given in option (1).

Therefore, Option (1) will be the answer.

3 0
2 years ago
Read 2 more answers
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