3. Four amateur miniature golfers attempt to finish 100 holes under par several times. Each round of 100, the number of holes th
1 answer:
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Given:
m(ar KN) = 2x + 151
m(ar LN) = 61°
m∠NMK = 2x + 45
To find:
m∠NMK
Solution:
By property of circle:
<em>If a tangent and a secant intersect outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>
Multiply by 2 on both sides, we get
Subtract 90 from both sides.
Subtract 2x from both sides.
Substitute x= 0 in m∠NMK.
m∠NMK = 2x + 45
= 2(0) + 45
= 45
Therefore m∠NMK = 45.
The number of times the spinner landed on a space numbered greater than 4 = 167
Step-by-step explanation:
Step 1 :
Given,
Number of equal area spaces in the spinner = 6
Number of times the spinner was spun = 500
We need to find the number of times the spinner landed on a space numbered greater than 4
Step 2 :
Total number of outcome = 6
Favorable outcomes are = Numbers greater than 4 = 5,6
Total number of favorable outcome = 2
Therefore Probability that the spinner will land on a number that is greater than 4 is =
The number of times that the spinner landed on a space numbered greater than 4 = 500 × = 166.67 = 167 (rounded off to the nearest integer)
Step 3 :
Answer :
The number of times the spinner landed on a space numbered greater than 4 = 167