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asambeis [7]
2 years ago
15

Greg bought 2 boxes of balloons he used half of them to decorate his yard he used 40 to decorate his porch he used the rest insi

de his house how many balloons did he use
Mathematics
1 answer:
german2 years ago
8 0
Well, he used one box to decorate his yard, that's for sure. Then he used 40 from the other box to decorate his porch and the rest inside his house. That rest might be anything between 1 and infinity. So there were at least 41 balloons in each box. I think the question is incomplete, please doublecheck it so I'll be able to give you more specific result.
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If f(x) = 3 – 2x and 1/x+5, what is the value of (f/g)(8)? –169 –1 13 104
Basile [38]
I'm assuming that this is the complete question.
If f(x) = 3 – 2x and g(x)=1/(x+5), what is the value of (f/g)(8)? a) –169       b) –1      c) 13     d) 104
x = 8
f(x) = 3 -2xf(8) = 3 - 2(8) = 3 - 16 = -13
g(x) = 1/(x+5)g(8) = 1/(8+5) = 1/13
(f/g)(8)f(8)/g(8) = -13/ (1/13) = -13 * 13 = -169  Choice A :)
8 0
2 years ago
Read 2 more answers
Alexis has a rectangular piece of red paper that is 4 cm wide its length is twice its width she Glooze a rectangular r Alexis ha
UNO [17]

Are you looking for the area or the perimeter?

Perimeter: 24

Area: 32

Hope this helped!

-TTL

5 0
2 years ago
Read 2 more answers
One way to measure whether the trees in the Wade Tract are uniformly distributed is to examine the average location in the north
tatyana61 [14]

Answer:

Null hypothesis be H₀ : μ = 100

Alternative hypothesis Hₐ : μ < 100

There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100

Step-by-step explanation:

Here we have;

Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100

Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level

Proposed average location in Wade Tract, μ = 100

Sample mean, \bar x = 99.74

Standard deviation, s = 58

Sample size, n = 584

The t test formula is therefore;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}}

Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We have t_{\alpha /2} = -1.65

Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;

There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.

7 0
2 years ago
Imogen sees a design for a garden in a magazine. She changes the scale because she wants a smaller garden. The figure below show
faust18 [17]

Answer:

Length A of the magazine garden is 28 feet is true.

Length B of the Magazine garden is 17.5 feet is true.

Length C of the Magazine garden is 35 feet is true.

Step-by-step explanation:

Please refer the attached figure.

Given:-

Magazine Scale is 1 inch = 3.5 feet.

Imogen's scale is 2 inches = 6 feet,

Therefore Imogen's scale is 1 inch = 3 feet.

In Triangle ABC,

side a = 8 inches, side b= 5 inches, side c= 10 inches.

To find:- The correct 3 options(actual size of sides of triangle  ABC).

Solution:-

In triangle ABC,

Let,

AB=side a =8 inches

BC=side b =5 inches

AC=side c= 10 inches

Now, as per the given scale's of Magazine and Imogen's we can find the actual sizes.

Length A as per Magazine scale (1 inch = 3.5 feet) is,

\therefore Length\ A=8\times 3.5   -------------(as per scale)

\therefore Length A=28\ feet

and Length A as per Imogen's scale(1 inch =3 feet) is,

AB = side a

\therefore Length\ A=8\times 3  -------------(as per scale)

\therefore Length A=24\ feet

Therefore Length A of the magazine garden is 28 feet is true.

Now, Length B as per Magazine scale (1 inch = 3.5 feet) is,

BC = side b

\therefore Length\ B=5\times 3.5

\therefore Length B=17.5\ feet

Length B as per Imogen's scale (1 inch = 3 feet) is,

BC = side b

\therefore Length\ B=5\times 3

\therefore Length B=15\ feet

Therefore Length B of the Magazine garden is 17.5 feet is true.

Now, Length C as per Magazine scale (1 inch = 3.5 feet) is,

AC = side c

\therefore Length\ C=10\times 3.5

\therefore Length C=35\ feet

Length B as per Imogen's scale (1 inch = 3 feet) is,

AC = side c

\therefore Length\ C=10\times 3

\therefore Length B=30\ feet

Therefore Length C of the Magazine garden is 35 feet is true.

8 0
2 years ago
Read 2 more answers
An article in Fire Technology, 2014 (50.3) studied the effectiveness of sprinklers in fire control by the number of sprinklers t
gregori [183]

Answer:

probability that all of the sprinklers will operate correctly in a fire: 0.0282

Step-by-step explanation:

In order to solve this question we will use Binomial  probability distribution because:

  • In the question it is given that the sprinklers activate correctly or not independently.
  • The number of outcomes are two i.e. sprinklers activate correctly or not.

A binomial distribution is a probability of a success or failures outcomes in an  repeated multiple or n times.

Number of outcomes of this distributions are two.

The formula is:

b(x; n, P) = C_{n,x}*p^{x}  * (1 - p)^{n-x}

b = binomial probability  also represented as P(X=x)

x =no of successes

P = probability of a success on a single trial

n = no of trials

C_{n,x} is calculated as:

C_{n,x} = n! / x!(n – x)!

        = 10!  / 10!(10-10)!

        = 1

According to given question:

probability of success i.e. p = 0.7 i.e. probability of a sprinkler to activate correctly.

number of trials i.e. n = 10 as number of sprinklers are 10

To find: probability that all of the sprinklers will operate correctly in a fire

X = 10 because we have to find the probability that "all" of the sprinklers will operate correctly and there are 10 sprinklers so all 10 of them

So putting these into the formula:

P(X=x) = C_{n,x}*p^{x}  * (1 - p)^{n-x}

           = C₁₀,₁₀ * 0.7¹⁰ * (1-0.7)¹⁰⁻¹⁰

           =  1 * 0.0282 * (0.3) ⁰

           = 1 * 0.0282 * 1

  P(X=x)        = 0.0282

5 0
2 years ago
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