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ch4aika [34]
2 years ago
13

Calculate the mass of calcium carbide produced if 1770 kJ of heat is absorbed.

Chemistry
1 answer:
Flauer [41]2 years ago
7 0

Answer:

m=243.72g

Explanation:

Hello,

For the given chemical reaction:

CaO(s) + 3 C(s) \rightarrow CaC_2(s) + CO(g)

Whose heat of reaction is 464.8 kJ/mol which means that energy is absorbed due to the chemical reaction, we can compute the moles of calcium carbide via the following relationship:

n=\frac{1770kJ}{464.8 kJ/mol}\\ \\n=3.81mol

Then, since the molar mass of calcium carbide is 64 g/mol, the yielded mass turns out:

m=3.81mol*\frac{64g}{1mol}\\ \\m=243.72g

Best regards.

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Serhud [2]

Answer: 0.635 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{5.15g}{162.4g/mol}=0.0317moles  

V_s = volume of solution  = 150 ml

Molarity=\frac{0.0317\times 1000}{150ml}=0.2114M

FeCl_3\rightarrow Fe^{3+}+3Cl^-

as 1 mole of FeCl_3 gives 3 moles of Cl^- ions

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Molarity of Cl^- = 0.635 M

8 0
2 years ago
In the synthesis of barium carbonate from an alkali metal carbonate (M2CO3 where M is one of the alkali metals) a student genera
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Answer:

0.019 moles of M2CO3

Explanation:

M2CO3(aq) + BaCl2 (aq) --> 2MCl (aq) + BaCO3(s)

From the equation above;

1 mol of  M2CO3 reacts to produce 1 mol of BaCO3

Mass of BaCO3 formed = 3.7g

Molar mass of BaCO3 = 197.34g/mol

Number of moles = Mass / Molar mass = 3.7 / 197.34 = 0.0187  ≈ 0.019mol

Since 1 mol of M2CO3 reacts with 1 mol of BaCO3,

1 = 1

x = 0.019

x = 0.019 moles of M2CO3

3 0
2 years ago
What type of bond would form between two atoms of selenium?
siniylev [52]

Answer:

the correct answer is B

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8 0
2 years ago
2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?
otez555 [7]

Answer:

100g/mol

Explanation:

Given parameters:

Mass of unknown gas  = 2g

Volume of gas in flask  = 500mL  = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;  

        1 mole of substance occupies 22.4dm³ of space at STP

    Therefore,

            0.5dm³ will have  0.02mole at STP

                     

Now;

   Number of moles  = \frac{mass}{molar mass}  

      Molar mass  = \frac{mass}{number of moles}   = \frac{2}{0.02}   = 100g/mol

4 0
2 years ago
What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride
Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol  = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0
2 years ago
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