Question

A 0.0200 M NaCl solution was formed when 38.0 grams of NaCl was dissolved in enough water. What was the total volume of the solution formed?

Answer 1

Answer: The volume of the solution formed will be 32.5 L.

Explanation:

Molarity is defined as the amount of solute present in 1 L of solution. The equation used to determine molarity of the solution follows:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of the solution = 0.02 mol/L

Mass of NaCl = 38 grams

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

$0.02mol=\frac{38g}{58.5g/mol\times V_s}\\\\\text{Volume of the soltion}=32.5L$

Hence, the volume of the solution formed will be 32.5 L.

Answer 2

First calculate the no of moles, that is 38 grams divided by molar mass which is 58.43 g/mol. The no of moles is 0.65 moles. Concentration= no of moles divided by volume in litre. From the above formula, volume= no of moles divided by concentration. So to get the total volume 0.65 moles divided by 0.02M (mol/L) which gives 32.5 L.