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PilotLPTM [1.2K]
2 years ago
13

Leaded gasoline contains an additive to prevent engine knocking. On analysis, the additive compound is found to contain carbon,

hydrogen, and lead (Pb) (hence, leaded gasoline). When 51.36 g of this compound is burned in a combustion analysis apparatus, 55.90 g of CO2 and 28.61 g of H2O are produced. Determine the empirical formula of the gasoline additive.
Chemistry
1 answer:
poizon [28]2 years ago
5 0

Answer:

PbC(8)H(20)

Explanation:

51.36g of the leaded gasoline when combusted yielded 55.90 CO2 and 28.61 H2O,

Fraction of carbon in the sample = molecular mass of carbon / molecular mass of CO2* mass of CO2 produced = 12.0107/ 44.01 * 55.90 = 15.26 g

Similarly,

Mass of hydrogen present in the sample = molecular mass of hydrogen/ molecular mass of water * Mass of water produced = 2(1.00784)/18.0153 *28.61 = 3.201

The mass of the compound was 51.36, mass of lead present in the sample = total mass of the sample - (mass of carbon + mass of hydrogen) = 51.36 - (15.26+3.201) = 32.899

To find the mole ratio of the substances in the compound, lead = mass of lead / molecular mass of lead = 32.899/ 207.2 = 0.159

Carbon = 15.26/12.0107 = 1.271

Hydrogen = 3.201/ 1.00784 = 3.1761

Divide each mole by the smallest mole to find the mole ratio

Lead = 0.159/0.159 =1

Carbon = 1.271/0.159 = 7.994 approx 8

Hydrogen = 3.1761/0.159 = 19.975approx 20

Therefore the empirical formula which is different from the molecular because it is the simplest form of the substance is equal to PbC8H20

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Draw a structure containing only carbon and hydrogen that is a stable alkyne of five carbons containing a ring.
stepladder [879]

Answer:

                     Ethynylcyclopropane is the stable isomer for given alkyne.

Explanation:

                     In order to solve this problem we will first calculate the number of Hydrogen atoms. The general formula for alkynes is as,

                                                    CₙH₂ₙ₋₂

Putting value on n = 5,

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Also, the statement states that the compound contains one ring therefore, we will subtract 2 hydrogen atoms from the above formula i.e.

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Hence, the molecular formula for given compound is C₅H₆

Below, 4 different isomers with molecular formula C₅H₆ are attached.

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                                      Compounds 3-ethylcycloprop-1-yne, <u>cyclopentyne </u>and 3-methylcyclobut-1-yne are highly unstable. The main reason for the instability is the presence of triple bond in three, five and four membered ring. As the alkynes are linear but the C-C-H bond in these compound is less than 180° which will make them highly unstable.

5 0
2 years ago
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nadya68 [22]
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2 years ago
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