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2 years ago

What is the IUPAC name of the following compound?

Chemistry

1 answer:

pentagon [3]2 years ago

3 0

Answer:

(d) 3,7-dimethyl-4-nonyne.

Explanation:

Hello,

In this case, considering the attached picture on which you can see that the main chain has nine carbon atoms, one tripe bond at the fourth carbon and two methyl radicals at the third and seventh carbons respectively, by following the IUPAC rules, the name would be: (d) 3,7-dimethyl-4-nonyne since the chain must start at the side closest to the first triple bond due to its priority and subsequently considering the present radicals.

Best regards.

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imagine you or your family member experienced a medical emergency. explain two reasons when and why confidentiality would be imp

Hatshy [7]

<span>One reason confidentiality would be important at a time of a medical emergency is if the patient didn't want people to know about the emergency so that they wouldn't worry. Another reason is for instance if that medical emergency was something that the patient considered embarrassing then they wouldn't want people to know.</span>

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2 years ago

In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)

Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.6 L

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}$

${V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L$

${V_2}=0.27\ L$

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

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2 years ago

Draw the condensed structural formula in the equation for the saponification of trimyristin with koh

Ludmilka [50]

Explanation: Saponification reaction is a reaction in which hydrolysis of fats takes place under basic conditions giving glycerol and a salt of corresponding fatty acid.

We are given a Fatty acid called as Trimyristin.

Its reaction with KOH leads to the formation of soap and is given by the equation:

$Trimyristin+3 KOH\rightarrow Glycerol+Soap$

$C_{45}H_{86}O_6+3KOH\rightarrow C_3H_5(OH)_3+3CH_3(CH_2)_{12}CO_2K$

The condensed structural formula for the equation is given in the image attached.

4 0

2 years ago

Read 2 more answers

The Rydberg constant is 3.3 x 10 15 Hz. this value is also

mina [271]

Answer:

Rydberg constant 3.3 x 10¹⁵ Hertz is equal to 1.090 x 10⁷ m⁻¹

Explanation:

Given;

Rydberg constant as 3.3 x 10¹⁵ Hz

1 Rydberg constant = 3.3 x 10¹⁵ Hz

1 Rydberg constant = 1.090 x 10⁷ m⁻¹

Therefore, Rydberg constant 3.3 x 10¹⁵ Hertz is equal to 1.090 x 10⁷ m⁻¹

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2 years ago

Read 2 more answers

Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis

almond37 [142]

Answer: a) $BaCl_2$

b) $BiO_3H_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles$

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = $\frac{0.48}{0.48}=1$

For O = $\frac{0.96}{0.48}=2$

The ratio of Ba: Cl= 1:2

Hence the empirical formula is $BaCl_2$

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= $\frac{0.38}{0.38}=1$

For O = $\frac{1.15}{0.38}=3$

For H= $\frac{1.16}{0.38}=3$

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is $BiO_3H_3$

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2 years ago