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-BARSIC- [3]
2 years ago
13

Which pairs of reactants will result in a chemical reaction? Refer to the activity series as needed. Pb ( s ) + MgCl 2 ( aq ) Pb

(s)+MgCl2(aq) Al ( s ) + AgClO 3 ( aq ) Al(s)+AgClO3(aq) Cd ( s ) + CuNO 3 ( aq ) Cd(s)+CuNO3(aq) Pt ( s ) + CoBr 2 ( aq )

Chemistry
1 answer:
GrogVix [38]2 years ago
4 0

Answer:

Al (s) + AgClO3 (aq) will result in a chemical reaction.

Al(s) + 3AgClO₃(aq) -----> Al(ClO₃)₃(aq) + 3Ag(s)

Cd(s) + CuNO3(aq) will also result in a chemical reaction.

Cd(s) + 2CuNO₃ -----> Cd(NO₃)₂ + 2Cu

Explanation:

For chemical reactions, metals lower on the activity series cannot normally displace ions of metals higher than them in the activity series.

Metals at the lower end of the activity series are not easily oxidized.

The activity series is attached to this solution. (Note: Cadmium is not on the attached chart, but Cadmium is between Iron (Fe) & Cobalt (Co) on the activity series)

- Pb is way lower Mg in the activity series, hence, it cannot become oxidized by displacing Mg2+ ion in solution.

- Al is way higher than Ag in the activity series. Hence it will easily be oxidized and displace displace Ag from it's solution easily.

- Cadmium will displace Copper in solution too because Cd is higher than Cu on the activity series.

- Platinum cannot displace Cobalt from solution as Pt is lower than Co on the activity series.

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The following do not represent valid ground-state electron configurations for an atom either because they violate the Pauli excl
svetoff [14.1K]

Answer:

<em>For both cases the answer is C</em>

Explanation:  

We can see that the orbitals are not filled in the order of increasing energy and the Pauli exclusion principle is violated because it does not follow the correct order of the electron configuration; In the first exercise after the 2s2 orbital, the 2p2 orbital follows.

For the second exercise, you must start in order with level 1 and correctly filling each of the sublevels corresponding to each level until reaching level 7 and thus completing the desired number of electrons.

7 0
1 year ago
Read 2 more answers
Which solution contains the largest number of moles of chloride ions?
elixir [45]
Molarity = number of moles of solute/liters of solution
number of moles of solute = molarity x liters of solution

Part (a): <span>30.00 ml of 0.100m Cacl2
number of moles of CaCl2 =  0.1 x 0.03 = 3x10^-3 moles
1 mole of CaCl2 contains 2 moles of chlorine, therefore 3x10^-3 moles of CaCl2 contains 6x10^-3 moles of chlorine

Part (b): </span><span>10.0 ml of 0.500m bacl2
number of moles of BaCl2 = 0.5 x 0.01 = 5x10^-3 moles
1 mole of BaCl2 contains 2 moles of chlorine, therefore 5x10^-3 moles of BaCl2 contains 10x10^-3 moles of chlorine

Part (c): </span><span>4.00 ml of 1.000m nacl
number of moles of NaCl = 1 x 0.004 = 0.004 moles
1 mole of NaCl contains 1 mole of chlorine, therefore 4x10^-3 moles of NaCl contains 4x10^-3 moles of chlorine

Part (d): </span><span>7.50 ml of 0.500m fecl3
number of moles of FeCl3 = 0.5 x 0.0075 = 3.75x10^-3 moles
1 mole of FeCl3 contains 3 moles of chlorine, therefore 3.75x10^-3 moles of FeCl3 contains 0.01125 moles of chlorine

Based on the above calculations, the correct answer is (d)</span>
5 0
2 years ago
Read 2 more answers
A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs
Mars2501 [29]
The answer is (4) Add enough solvent to 30.0 g of solute to make 1.0 L solution. The molarity is calculated using volume of the solution. When solute dissolving, the total volume will change. So the final volume of solution need to be 1.0 L.
4 0
2 years ago
Silver chloride is formed by mixing silver nitrate and barium chloride solutions. What volume of 1.50 M barium chloride solution
konstantin123 [22]

Answer:

1.22 mL

Explanation:

Let's consider the following balanced reaction.

2 AgNO₃ + BaCl₂ ⇄ Ba(NO₃)₂ + 2 AgCl

The molar mass of silver chloride is 143.32 g/mol. The moles corresponding to 0.525 g are:

0.525 g × (1 mol/143.32 g) = 3.66 × 10⁻³ mol

The molar ratio of AgCl to BaCl₂ is 2:1. The moles  of BaCl₂ are 1/2 × 3.66 × 10⁻³ mol = 1.83 × 10⁻³ mol.

The volume of 1.50 M barium chloride containing 1.83 × 10⁻³ moles is:

1.83 × 10⁻³ mol × (1 L/1.50 mol) = 1.22 × 10⁻³ L = 1.22 mL

8 0
1 year ago
What quantum numbers specify these subshells? 2S, 6P, and 3D. (The answer is n= and L=)
statuscvo [17]
N = 1
l = from 0 to (n-1)
ml = -1... + 1
ms = 1/2 or -1/2

eg = 2s
n = 2, m = 0, n = 0
s = 1/2, -1/2

hope this help
4 0
2 years ago
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