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2 years ago

The data set shows how many points mark scored in each basketball game he played this season

Mathematics

1 answer:

kifflom [539]2 years ago

4 0

Answer:

So, filling the box plot from left to right, we have the following values;

1 , 5, 8 , 11, 16

Step-by-step explanation:

Here in this question, we are interested in fixing the values in the box plot from the data given.

Mathematically, the box plot shows 5 values;

going from left to write at each point, we have

minimum value

lower quartile also called Q1

Median

Upper quartile also called Q3

and lastly;

Maximum value

From the question;

minimum value = 1 while maximum value = 16

So also, the median should be easy to obtain.

the median is simply the middle number;

We have 15 numbers in the set;

So therefore the median is the 8th number, counting from any of the ends of the arranged set.

From the data, this is a value of 8

Now let’s calculate the lower quartile

To calculate the lower quartile, we just add 1 to the total and divide by 4

= (N + 1)/4

That would be (15 + 1)/4 = 16/4 = 4

So the lower quartile will be the 4th term which is 5

Now, let’s calculate the upper quartile;

= (N + 1) * 3/4 = (15 + 1)* 3/4 = 3/4 * 16 = 12th term

By counting, this is 11

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Find the first partial derivative:<br><br> f(x, y) = y^5 -3xy

Romashka-Z-Leto [24]

Partial derivative is derivative over only 1 variable.
here we have 2 variables so it depends on which variable you want to make partial derivative.

case 1.
df/dx = -3y

case 2
df/dy = 5y^4 - 3x

8 0

2 years ago

Jun and deron are applying for summer jobs at a local restaurant. after interviewing them, the restaurant owner says, "the proba

mr Goodwill [35]

<span>As restaurant owner The probability of hiring Jun is 0.7 => p(J) The probability of hiring Deron is 0.4 => p(D) The probability of hiring at least one of you is 0.9 => p(J or D) We have a probability equation: p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D) p(J and D) = 1.1 - 0.9 = 0.2 So the probability that both Jun and Deron get hired is 0.2.</span>

6 0

2 years ago

If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei

MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is ${11 \choose 3} = 165 .$ As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is ${7 \choose 3} = 35$ . Thus, there are only 35 ways to distribute the blackboards in this case.

4 0

2 years ago

Rachel traveled to five different areas (A, B, C, D, and E) to study the number of buckeye butterflies and the number of monarch

vekshin1

Answer:

C and E

Step-by-step explanation:

Have a great day! THanks!

8 0

2 years ago

Read 2 more answers

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra

alina1380 [7]

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

The fitted regression is Time = −7.126 + .0214 Distance

Based on a sample size n = 20

And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df = 18

At the level of significance ∝ = 0.05 and degree of freedom df = 18

For a right tailed test t, the critical value from the t table is :

$t_{0.05, 18} =$ 1.734

5 0

2 years ago