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den301095 [7]
2 years ago
15

Jun and deron are applying for summer jobs at a local restaurant. after interviewing them, the restaurant owner says, "the proba

bility that i hire jun is 0.7, and the probability that i hire deron is 0.4. the probability that i hire at least one of you is 0.9." what is the probability that both jun and deron get hired?
Mathematics
1 answer:
mr Goodwill [35]2 years ago
6 0
<span>As restaurant owner The probability of hiring Jun is 0.7 => p(J) The probability of hiring Deron is 0.4 => p(D) The probability of hiring at least one of you is 0.9 => p(J or D) We have a probability equation: p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D) p(J and D) = 1.1 - 0.9 = 0.2 So the probability that both Jun and Deron get hired is 0.2.</span>
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Ipatiy [6.2K]

Answer:

He needs to sell the rest of the oranges at 75 paisa each.

Step-by-step explanation:

Consider the given information that, Shishir bought 4000 orange at 70 paisa each.

Note: 1 rupees = 100 paisa

Thus, 70 paisa = 70/100 rupees = 0.70 rupees

Therefore, the cost price of 4000 oranges is:

4000×0.70 rupees = 2800 rupees

The selling price of 2000 oranges is:

2000×0.90 rupees = 1800 rupees

The number of oranges now Shishir have:

4000 - 2000 - 400 = 1600

He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:

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He earned 1800 rupees by selling 2000 oranges at 90 paisa. So, the remaining amount that he needs to make with 1600 oranges is:

3000 rupees - 1800 rupees = 1200 rupees

Therefore, the cost of one orange is:

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2 years ago
What expression is equivalent to (5z^2+3z+2)^2
nikdorinn [45]
Please see picture attached.

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2 years ago
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A. 2x3=6 and 6x12=72 so 78 is greater than 36

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Answer:

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Step-by-step explanation:

The average blood alcohol concentration (bac)  is modeled by the following function.

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In which t is measured in minuted.

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This is c'(t) when t = 5.

Using the derivative of the product.

Derivative of the product:

c(t) = f(t)*g(t)

c'(t) = f'(t)*g(t) + f(t)*g'(t)

In which problem:

f(t) = 0.0225t

g(t) = e^{-0.0467t}

So

c'(t) = 0.0225e^{-0.0467t} - 0.0225*0.0467*te^{-0.0467t}

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