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2 years ago

The quantities xxx and yyy are proportional.

Mathematics

1 answer:

Valentin [98]2 years ago

5 0

Answer:

The answer is 0.5

Step-by-step explanation:

If you do 4.5 divided by 9 you get 0.5

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The half-life of cesium-137 is 30 years. Suppose we have a 170 mg sample.(a) Find the mass that remains after t years.(b) How mu

saul85 [17]

Answer:

212.9 years

Step-by-step explanation:

Given that the half-life of cesium-137 is 30 years. Suppose we have a 170 mg sample

P0 = 175

P(30) = 87.5

So we can write equation as

$P(t) = 170(\frac{1}{2} )^{\frac{t}{30} }$

b) After 60 years t = 30

In 30 years it becomes half and hence in 60 years it would become 1/4

i.e. $P(60) = 137(1/2^4) = 34.25$ mg

c) If P(t) =1, let us find t

$137(1/2)^{\frac{t}{30} } =1\\\\n = 7.098 years\\n = 7.1*30 = 212.9 years$

212.9

5 0

2 years ago

Team A faces loses of 5,876 points in Round 1 . How much is the loss of points for each of the 26 players of Team A if the loss

Svetllana [295]

Answer:

226 points were lost per player

Step-by-step explanation:

Since we are evenly spreading the points between all 26 players, we need to solve using division.

Basically, we are dividing the 5876 points among the 26 players.

5876/26 = 226

Therefore, if the points were spread evenly among all 26 players, each player would lose 226 points.

6 0

2 years ago

Harmony earns a \$42{,}000$42,000dollar sign, 42, comma, 000 salary in the first year of her career. Each year, she gets a 4\%4%

saveliy_v [14]

Answer:

FV(n)=42,000(1.04)^n

Step-by-step explanation:

FV=PV(1+r/n)^nt

Where

FV=future value

PV=present value

r=interest rate

n=number of periods

t=time (years)

PV=42,000

r=4%=0.04

n=1

t=n

FV(n)=p(1+r/n)^nt

=42,000(1+0.04/1)^1*n

=420000(1+0.04)^n

=42,000(1.04)^n

FV(n)=42,000(1.04)^n

7 0

2 years ago

C. Assessment

Crazy boy [7]

1. B
2. A
3. A
All of theses are true

4 0

2 years ago

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = three-quarters x 2 + 2x − 5 f(x) = StartFraction 4 Over x

tatyana61 [14]

Answer:

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

Step-by-step explanation:

Given

$f(x) = -8x^3 - 16x^2 - 4x\\f(x) = \frac{3}{4}x^2 + 2x - 5\\f(x) = \frac{4}{x^2} - \frac{2}{x} + 1\\f(x) = 0x^2 - 9x + 7$

Required

Which of the above is a quadratic function

A quadratic function has the following form;

$ax^2 +bx + c = 0 \ where \ a\neq 0$

So, to get a quadratic function from the list of given options, we simply perform a comparative test of each function with the form of a quadratic function

$1.\ f(x) = -8x^3 - 16x^2 - 4x$

This is not a quadratic function because it follows the form $f(x) = ax^3 + bx^2 + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

This function has an exact match with $ax^2 +bx + c = 0 \ where \ a\neq 0$

By comparison; $a = \frac{3}{4}\ b = 2\ and\ c = -5$

$3.\ f(x) = \frac{4}{x^2} - \frac{2}{x} + 1$

This is not a quadratic function because it follows the form $f(x) = \frac{a}{x^2} + \frac{b}{x} + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$

$4.\ f(x) = 0x^2 - 9x + 7$

This is not a quadratic function because it follows the form $f(x) = ax^2 +bx + c = 0\ but\ a = 0$

Unlike the quadratic function where $a\neq 0$

So, from the list of given options, only $2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$ satisfies the given condition

5 0

2 years ago