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PIT_PIT [208]
2 years ago
14

Misha found that the equation -|2x-10|-1=2 had two possible solution x=3.5and x =-6.5. Which explains whether or not her solutio

ns are correct
Mathematics
2 answers:
Pie2 years ago
5 0

Answer:

She is not correct.

Step-by-step explanation:

Given : Misha found that the equation - |2x-10|-1=2  had two possible solution x=3.5 and x =-6.5.

To find : Explains whether or not her solutions are correct.

Solution :

The first thing we solve the equation to get solution,

- |2x-10|-1=2

Add 1 on both side of equation :

 - |2x-10|-1+1=2+1

 - |2x-10|=3

Multiply both sides of the equation by -1:

 - |2x-10|(-1)=3(-1)

 |2x-10|=-3

We observe that the result of the expression in absolute value is -3.

The result of an absolute value function is always greater than or equal to zero.

Which implies , the equation has no solution.

Therefore, Misha solutions were incorrect.

Vika [28.1K]2 years ago
3 0
<span>-|2x-10|-1=2 has NO solutions, because the absolute value function is never negative.  Can be 0, can be positive, but can NOT be negative.

</span>
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On average, water flows over a particular water fall at a rate of 2.05 x 105 cubic feet per second. One cubic foot of water weig
iren [92.7K]

Answer:

5.024 × 10^8 tons /day

Step-by-step explanation:

This question has to deal with conversion

We are told in the question that:

On average, water flows over a particular water fall at a rate of 2.05 x 10^5 cubic feet per second.

Water flow rate = 2.05 × 10^5 ft³/s

From the question,

One cubic foot of water weighs 62.4 lb.

1 ft³ = 62.4 lb

1 ton = 2200 lb

We are to calculate the flow rate in tons per day

Hence,

1 ft³ = 62.4 lb

2.05 × 10^5 ft³ =

Cross Multiply

2.05 × 10^5 × 62.4

= 12792000lb

Hence the water flow rate = 12792000lb/s

From the question,

2200 lb = 1 ton

12792000 Ib =

Cross Multiply

12792000lb × 1 ton/2200 lb

= 5814.5454545 tons

Hence the water flow rate = 5814.5454545 tons/second

We want the flow rate to be in tons/day

1 ton / second = 86400 tons / day

5814.5454545 tons/second = x tons/ day

Cross Multiply

x = 5814.5454545 tons/second × 86400 tons /day/ 1 ton / second

= 502376727.27 tons/day

= 5.0237672727 × 10^8 tons/day

Approximately ≈ 5.024 × 10^8 tons /day

Therefore, the rate of water flow in tons of water per day is 5.024 × 10^8 tons of water /day

7 0
2 years ago
What is 63.4 divided by 20
Zanzabum
317 is the answer you are looking for.
6 0
2 years ago
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Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.
vodka [1.7K]

Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation (\sqrt[3]{128} )^{x}\\

According to one of the law of indices,

(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}

Applying this law to the question;

(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

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2 years ago
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What is the simplified form of the ninth root of x times the ninth root of x times the ninth root of x times the ninth root of x
Tomtit [17]
Let's convert the task into an example, simplifyng which will make us able to get the answer.
So, according to the task: \sqrt[9]{x} *  \sqrt[9]{x} *  \sqrt[9]{x} *  \sqrt[9]{x} &#10;&#10;=   \sqrt[1/ 9 ]{x} *  \sqrt[1/9]{x} *  \sqrt[1/9]{x} *  \sqrt[1/9]{x}

Now we can simplify: \sqrt[1/9]{x} + 1/9+1/9+1/9&#10;&#10;= x^{4/9}

So the answer is  <span>C:x to the four ninths power</span>
6 0
2 years ago
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Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.
Ede4ka [16]

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

Step-by-step explanation:

We need to  describes Catron’s error?

The steps are:

Step 1: (Negative 9) (2 + two-fifths)

Step 2: (Negative 9) (Negative 2) + (negative 9) (two-fifths)

Step 3: Negative 18 + (negative 9) (two-fifths)

Step 4: (negative 27) (two-fifths)

Solution: Negative StartFraction 54 over 5 EndFraction = Negative 10 and four-fifths

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

<u>Solving </u>

Solving the equation by removing the error:

Step 1: (Negative 9) (2 + two-fifths)

taking LCM of 2 and two-fifths (2/5)

Step 2: (Negative 9) (twelve-fifths)

Step 3: (Negative 9*twelve)-fifths

Step 4: Negative one hundred and eight- fifths

Solution: Negative StartFraction -108 over 5 EndFraction = Negative one hundred and eight- fifths

Keywords: Solving Expressions

Learn more about Solving Expressions at:

  • brainly.com/question/2456302
  • brainly.com/question/7014769
  • brainly.com/question/11007572
  • brainly.com/question/11334714

#learnwithBrainly

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2 years ago
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