Answer:
Step-by-step explanation:
given that a bag contains 6 balls labelled A to F.
Given that a ball is drawn at random and its letter is recorded as outcome.
Since each ball is equally likely to be drawn the sample space for one ball drawing is
S = {A,B,C,D,E,F} and n(S) = 6
Let G be the event of choosing a lable from D to F
G = The event of choosing a label from D to F= {D,E,F} n(A) = 3
Answer:
Diameter of wheel in millimetres is 660.4
Step-by-step explanation:
Diameter of wheel in inches = 26
given
1 inch = 25.4 millimeters
multiplying RHS and LHS by 26
26*1 inch = 26*25.4 millimeters
=>26 inch = 660.4 mm.
Thus, diameter of wheel in millimetres is 660.4
Answer:
24
Step-by-step explanation:
The total capacity of the trailer is 1,050 kg.
An 82-kg crate is already loaded on the trailer.
We subtract 82 kg from 1,050 kg to find out the amount of weight still available.
1,050 kg - 82 kg = 968 kg
The trailer can still carry another 968 kg.
Each additional crate weighs 40 kg.
We divide 968 kg by 40 kg to calculate the number of crates that can still be loaded.
(968 kg)/(40 kg) = 24.2
Since we cannot place 0.2 of a crate, we round 24.2 down to 24.