Answer:
Option D is the correct answer to the following question.
Explanation:
The following option is correct because three sets type variable i.e., "fruit", "fruit2", "fruit3" has contain the same values in it and then they ask for the option is correct if the all are equal and in the option c, there is the if statement in which check the condition if the variable "fruit" is equal to the variable "fruit2" and the variable "fruit" is equal to the variable "fruit3".
so, that' why the following option is correct.
The option A is not correct because there is no equal function in python and we use the operator == to check the condition.
The option B is incorrect because we can see that there is not equal to (!=) operator.
The option D is incorrect because we can see that there is an or operator are used which means if any of the conditions is true then, they return either the other condition is false.
They are versatile because they can be used for all sorts of tasks. They can also do many of the same tasks in different ways. They are diligent because they will do a task thoroughly until it is finished.
They work at a constant speed to do the task. Unlike a human, they will not slow down or get bored or start making mistakes that they were not doing earlier. So once they are programmed correctly to do a task, they will do it diligently.
Answer:
The answer to the given question is "True".
Explanation:
In the database, we use the queries, when some error has occurred with queries so, the database provides a PL/SQL that is known as the procedural language that is the combination of the structured query language.
In this programming language, we use some triggers that are mainly available with database. The triggers are a set of the code that is executed automatically when an interruption has occurred.
That's why the answer to this question is "True"
Answer:
Answered below
Explanation:
#Program is written in Python programming language
sentence = input ("Enter sentence: ")
list_of_words = sentence.split()
for i in list_of_words:
#check if it is a digit
if not i.isdigit( ):
print ( i, sep= "\n" )
else:
#convert string to digits and double it
number = float( i )
double = number + number
print(double, sep="\n")
