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zhenek [66]
2 years ago
3

The number of salmon tagged in a wildlife program depends on the time in days since the beginning of the migration and can be mo

deled using the equation y = StartFraction 250 Over 1 + 2,499 e Superscript negative 0.4646x Baseline EndFraction. Complete the sentences interpreting the parts of the equation.
The function has an asymptote at
✔ y = 250
.

The point of inflection is
✔ (19.714, 125)
.

The limiting value represents the
✔ population of salmon

Someone please put random response
Mathematics
2 answers:
xxTIMURxx [149]2 years ago
6 0

Answer:

y = 250  、(19.714, 125)  、population of salmon

Step-by-step explanation:

edge2020

Goryan [66]2 years ago
6 0

Answer:

y = 250, (19.714, 125), population of salmon

Step-by-step explanation:

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At a large conference of teachers from a variety of subjects, a random sample of 50 mathematics teachers attending the conferenc
melamori03 [73]

Answer:

C. All mathematics teachers who have taken one or more courses in statistics

5 0
2 years ago
Find the measure of ∠EGC. Circle A with chords EF and CD that intersect at point G, the measure of arc EC is 50 degrees, the mea
miv72 [106K]

Answer:

m∠EGC=70°

Step-by-step explanation:

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite

so

m∠EGC=(1/2)[arc EC+arc DF]

<u><em>Find the value of x</em></u>

we have

m∠EGC=(7x+7)°

arc EC=50°

arc DF=10x°

substitute and solve for x

(7x+7)°=(1/2)[50°+10x°]

14x+14=50+10x

14x-10x=50-14

4x=36

x=9

<u><em>Find the measure of angle EGC</em></u>

m∠EGC=(7x+7)°

substitute the value of x

m∠EGC=(7(9)+7)°=70°

8 0
2 years ago
Read 2 more answers
A conditional relative frequency table is generated by row from a set of data. The conditional relative frequencies of the two c
Gre4nikov [31]
The right answer for the question that is being asked and shown above is that: "D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50." Given that a relative frequencies of 0.48 and 0.52, there will be an association between the categorical variables.<span>
</span>
4 0
2 years ago
Read 2 more answers
In ΔXYZ, m∠X = 70° and m∠Y = 88°. Which statement about the sides of ΔXYZ must be true?
Wewaii [24]

Answer:

Z must equal 22° because it will add up to 180° it is an acute scalene triangle

8 0
2 years ago
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
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