Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Answer:
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Step-by-step explanation:
A cyclist completes a journey of 500m in 22 seconds, part of the of the way at 10m/s and the remainder at 50m/s. how far does she travel at each speed? ... Let x = distance traveled at 10m/s and y = distance traveled at 50m/s. ... x+y=500. 50x+10y=11000. 50x+50y=25000. 50x+10y=11000. 40y=14000.
Answer:I am giving out 60 points if answer my question s
Step-by-step explanation:
Plz help
Step-by-step explanation:
Since f(0) = f(5) = f(8) = 0, we have f(x) = Ax(x - 5)(x - 8), where A is a real constant.
We know that f(10) = 17.
=> A(10)(10 - 5)(10 - 8) = 17
=> A(10)(5)(2) = 17
=> 100A = 17, A = 0.17.
Hence the answer is f(x) = 0.17x(x - 5)(x - 8).