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olga55 [171]
2 years ago
6

Water flows through a pipe at a rate of 89 cups per second. Express this rate of flow in gallons per hour.

Mathematics
1 answer:
Blababa [14]2 years ago
6 0
Answer: 20025 gallons per hour
89 times 60= 5340 cups in one minute
5340 times 60= 320,400 cups in one hour
Convert 320,400 cups into gallons and you will get 20025.
Not positive if this is correct but it’s better than nothing lol.
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Which statements about the graph of the function f(x) = –x2 – 4x + 2 are true? Select three options.
IceJOKER [234]

Answer:

The true statements about the graph of the function are:

The range of the function is {y : y ≤ 6} ⇒ 2nd

The function is increasing over the interval (–∞ , –2) ⇒ 3rd

The function has a positive y-intercept ⇒ 5th

Step-by-step explanation:

* Lets explain how to solve the problem

- The function f(x) = -x² - 4x + 2 is a quadratic function represented

  graphically by a downward parabola with maximum vertex

∵ The form of the quadratic function is f(x) = ax² + bx + c

∵ The coordinates of the vertex of the parabola are (h , k) where

   h = -b/2a and k = f(h)

∵ a = -1 , b = -4

∴ h = -(-4)/2(-1) = 4/-2 = -2

∵ k = f(h)

∴ k = -(-2)² - 4(-2) + 2 = -(4) - (-8) + 2

∴ k = -4 + 8 + 2 = 6

∴ The vertex of the parabola is (-2 , 6)

* Look to the attached figure to find the true statements

∵ The greatest value of the function is 6 ⇒ y-coordinate of the vertex

∵ The range of the function is the values y-coordinates of the points

  on the parabola

∴ The range of the function is {y : y ≤ 6}

- The domain of the function is {x : x ∈ R} or (-∞ , ∞)

∵ The value of y increasing after -∞ to the x-coordinate of the vertex

∵ x-coordinate of the vertex is -2

∴ The function is increasing over the interval (–∞ , –2)

- The parabola intersect the y-axis at point (0 , 2)

∵ The y-intercept is the intersection between the parabola and the

   y-axis

∵ The parabola intersect the y-axis at point (0 , 2)

∴ The y-intercept is 2

∴ The function has a positive y-intercept

9 0
2 years ago
Read 2 more answers
A number, x, rounded to 2 decimal places is 15.38<br>Write down the error interval for x.​
Stels [109]

Answer:

The error interval for x is:

[15.375,15.384]

Step-by-step explanation:

In order to determine the error interval for x, We have to get the all the number which could be rounded off to 15.38.

These number can be listed in order such as:

15.375   15.376   15.377   15.378   15.379   15.380   15.381   15.382   15.383   15.384  

Therefore, the error interval for x is:

[15.375,15.384]

5 0
2 years ago
Margo bought 7 pens from a bookstore. Some of the pens cost $3 each, and the rest cost $4 each. If she paid a total of $23 for t
e-lub [12.9K]

Answer: 5 Pens!

Step-by-step explanation: 5 Pens Would Be The Answer.

8 0
2 years ago
Rectangle lmno is rotated 90 degrees clockwise around the origin to create l’m’n’o which statement best describes the relationsh
vova2212 [387]

Answer:

The correct option is A: they are equidistant from origin

Step-by-step explanation:

Since the rotation is performed around the fixed axis on its origin, there will not be any change to the distances between the origin and the point n or n'. The size of the rectangle has neither increased or decreased so, it cannot be possible that the distance between the origin and the point n could change after the object is rotated.

Hope that answers the question, have a great day!

4 0
2 years ago
Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.

Answer: A_{CGD}=41.

8 0
2 years ago
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