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IrinaVladis [17]
2 years ago
9

The Bluebird Bakery sells more cookies when it lowers its​ prices, but this also changes profits. The profit function for the co

okies is f(x)=-500(x-0.45)^2+400. This function represents the profit earned when the price of a cookie is x dollars. The bakery wants to maximize its profits. Complete parts a to d below.
Mathematics
1 answer:
balu736 [363]2 years ago
7 0

Answer:

a. x≥0, cannot be negitive, price of cookie

b. 398.75 for .40c cookies, 355 for .75c cookies

c. .45

d. 400

Step-by-step explanation:

your welcome

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five people, each working 8 hours a day, can assemble 400 toys in a five day work week. what is the average number of toys assem
vladimir1956 [14]

The question asks for the rate of toys per hour.

So we shall divide the total toys assembled by the total hours.

Its a five day week.

The number of hours allotted per day are 8.

So total allotted during the week are 8 × 5 = 40 hours.

Number of toys made during the week are 400.

Hence the number of toys assembled per hour per person

= number of toys / number of hours

= 400 / 40

= 10 toys per hour per person.

The average number of toys assembled per hour per person is 10.


8 0
2 years ago
Read 2 more answers
When a test for steroids is given to soccer players, 98% of the players taking steroids test positive and 12% of the players not
anygoal [31]

Answer:

P = 0.300 or 30%

Step-by-step explanation:

There are two possibilities for a player to test positive:

1-) He does not take steroids (95%) with a 12% chance of testing positive:

P= 0.95 x 0.12

2-) He does take steroids (5%) with a 98% chance of testing positive:

P= 0.05 x 0.98

So the probability that a player tests positive is:

P = 0.95 x 0.12 + 0.05 x 0.98 =0.163

Therefore, the probability that a soccer player who tests positive takes steroids is:

P= \frac{0.05 * 0.98 }{0.163}\\P=0.300

5 0
2 years ago
Mustafa’s soccer team is planning a school dance as a fundraiser. The dj charges $200 and decorations cost $100. The team deci
Kaylis [27]

Question is Incomplete;Complete question is given below.

Mustafa’s soccer team is planning a school dance as a fundraiser. The DJ charges $200 and decorations cost $100. The team decides to charge each student $5.00 to attend the dance. If n represents the number of students attending the dance, which equation can be used to find the number of students needed to make $1,500 in profit?

5n - 300 = 1,500\\\\5n + 300 = 1,500\\ \\5n - 200 + 100n = 1,500\\\\5n - 100 -200n = 1,500

Answer:

5n - 300 = 1,500

Step-by-step explanation:

Given:

Charges of DJ = $200

Decoration charges = $100

Profit need to be made = $1500

Charges per student to attend the dance = $5

We need to write the equation to find the number of students for to attend the dance in order to make profit.

Solution:

Let the number of student be represented by 'n'.

Now we can say that;

Profit to be made should be equal to Charges per student to attend the dance multiplied by number of students minus sum of Charges of DJ and Decoration charges.

framing in equation form we get;

5n-(200+100)=1500\\\\5n-300=1500

Hence the equation to find the number of students attending the dance is 5n - 300 = 1,500

8 0
2 years ago
For z = 2cis Pi/6 , find z5 in rectangular form.
o-na [289]
z=2\mathrm{cis}\dfrac\pi6=2\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right)

By DeMoivre's theorem, you have

z^5=2^5\mathrm{cis}\dfrac{5\pi}6=32\left(\cos\dfrac{5\pi}6+i\sin\dfrac{5\pi}6\right)
\implies z^5=32\left(-\dfrac{\sqrt3}2+\dfrac12i\right)=-16\sqrt3+16i
8 0
2 years ago
BOXES Simon will make a box without a top by cutting out corners of equal size from a 22 inch by 15 inch sheet of cardboard and
il63 [147K]

Answer:

Volume of box is 432 in^3

Step-by-step explanation:

Let x be the side of square corner

Length of box after cutting corners =22-2x

Breadth of box after cutting corners =15-2x

Height =x

Volume of box = (22-2x)(15-2x)x

Volume of box =4x^3-74x^2+330x

Differentiate w.r.t x

\frac{dV}{dx}=12x^2-148x+330

Substitute derivative =0

12x^2-148x+330=0\\x=\frac{37-\sqrt{379}}{6},\frac{37+\sqrt{379}}{6}\\\frac{d^2V}{dx^2}=24x-148

at x=\frac{37-\sqrt{379}}{6}

\frac{d^2V}{dx^2}=24x-148=24(\frac{37-\sqrt{379}}{6} )-148=-77.87 < 0 hence maximum

at  x=\frac{37+\sqrt{379}}{6}

\frac{d^2V}{dx^2}=24x-148=24(\frac{37+\sqrt{379}}{6} )-148=77.87>0 hence minimum

So,Volume of box =4x^3-74x^2+330x=4(\frac{37-\sqrt{379}}{6} )^3-74(\frac{37-\sqrt{379}}{6} )^2+330(\frac{37-\sqrt{379}}{6} )=432.23 in^3

Hence Volume of box is 432 in^3

4 0
2 years ago
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