Answer:The formulas of ionic compounds are:
a)
b)
c)
d)
Explanation:
Formulas for the an ionic compounds is determine by:
Criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
(a) Copper bromide :Given that it contains 
ion.
(b) Manganese oxide : Given that it contains 
ion.
(c)Mercury iodide :Given that it contains 
(d) Magnesium phosphate :Given that it contains 
If we write the equation of the reaction that will take place, it is:
2HNO₃ + Na₂CO₃ → 2NaNO₃ + H₂CO3
The molar ratio of 2HNO₃ : Na₂CO₃ = 1 : 2
Therefore, we can set up the equation:
M₁V₁ = 2M₂V₂
Where the left side of the equation has the molarity and volume of HNO₃ and the right side has the molarity and concentration of Na₂CO₃. Substituting:
M₁ = (2 x 0.108 x 35.7) / 25
M₁ = 0.308 M
Answer: The rate of disappearance of 
is 
Explanation:
The given chemical reaction is:
The rate of the reaction for disappearance of is given as:
![\text{Rate of disappearance of }NO_2=-\frac{\Delta [NO_2]}{\Delta t}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20%7DNO_2%3D-%5Cfrac%7B%5CDelta%20%5BNO_2%5D%7D%7B%5CDelta%20t%7D)
Or,
where,
= final concentration of = 0.00650 M
= initial concentration of = 0.0100 M
= final time = 100 minutes
= initial time = 0 minutes
Putting values in above equation, we get:
Hence, the rate of disappearance of is
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