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kotegsom [21]
2 years ago
6

Find a solution to the linear equation 13x + y = 26 by filling in the boxes with a valid value of x and y.

Mathematics
1 answer:
KengaRu [80]2 years ago
6 0

Answer:

MOM

Step-by-step explanation:

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Ratna , who is in Mumbai , telephones her brother Ravi in Ahmedabad and speaks for 89 seconds . She is charged Rs 1.20 for every
blondinia [14]

Answer:

16.40

Step-by-step explanation:

3 min-> 180 s

180÷16≈11

11+1=12

12x1.20=14.40

14.40 + 2 = 16.40

7 0
1 year ago
The table shows Mr. Winkler’s schedule for paying off his credit card balance. A 5-column table with 4 rows. Column 1 is labeled
statuscvo [17]

Answer:

3

Step-by-step explanation:

6 0
2 years ago
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What is the percent of increase in the rent for Bob's apartment if it went from $560 to $616?
son4ous [18]

This is a two step problem. First, you need to find the difference (or increase) in the rent using subtraction.

616-560 = $56 increase

Now we need to figure what percent 56 is to the original amount (560)

We voice it like this:

56 is to 560 as x is to 100.

The equation looks like this:

56/560 - x/100

Cross multiply to cancel out the denominators.

56 x 100 = 560 x

5600 = 560 x

x = 10 percent.

Check it!

What is 10 percent of 560?

560 x .1 = $56

Was that your increase? ... yes.

5 0
2 years ago
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a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r
galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

4 0
2 years ago
Three kids play tennis at the same tennis courts. Mark plays every fourth day, David plays every seventh day and Bryan plays eve
Tatiana [17]

Answer:

Friday, August 17th

Step-by-step explanation:

Mark plays every 4th day

18th of July,21st of July,24th of July, 27th of July, 30th of July, 2nd of August,5th of August, 8th of August, 11th of August, 14th of August, 17th of August

Bryan plays every 6th day

18th of July, 23th of July, 28th of July, 2nd of August, 7th of August, 12th of August, 17th of August

David plays every seventh day

18th of July,24th of July,30th of July, 5th of August, 11th of August, 17th of August

The next day when all three of them will be at the court together is Friday, August 17th

7 0
2 years ago
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