Answer:
The answer is "GK=37, GH=14, and JK=19 ".
Step-by-step explanation:
In the question, an attachment file is missing.so, please find its attached file.
Given values:
GJ=4x+2
HK=6x-1
GK =37
Find:
HJ=?
GK = GJ+JK
= GJ+(HK-HJ)
= 4x+2+((6x-1)-x)
= 4x+2+6x-1-x
=
9x+1...(a)
Solve equation (a) and put the value of x in the equation:
=9(4)+1
=36+1
=37
find GH and JK=?
Given:
GK=37
Formula:
GH = GJ-HJ
= 4x+2- x
= 3x+2....(b)
Solve equation (a):
GK= 9x+1
37=9x+1
36=9x
x=4....(c)
put the value of equation (b) in equation (c)
GH = 3x+2
= 3(4)+2
= 12+2
= 14
Formula:
JK= HK-HJ
= 6x-1- x
= 5x-1
put the value of x in the above equation:
= 5(4)-1
= 20-1
=19
To expand (3 - 2x)^6 use the binomial theorem:
(x + y)^ n = C(n,0) x^ny^0 + C(n,1)x^(n-1) y + C(n,2)x^(n-2) y^2 + ...+ C(n,n+1)xy^(n-1) + C(n,n)x^0y^n
So, for x = 3, y = -2x , and n = 6 you get:
(3 - 2x) ^6 = C(6,0)(3)^6 + C(6,1)(3)^5 (-2x) + C(6,2) (3)^4 (-2x)^3 + C(6,3) (3^3) (-2x)^4 + C(6,4)(3)^2 (-2x)^4 + C(6,5) (3) (-2x)^5 + C(6,6) (-2x)^6
So, the sixth term is C(6,5)(3)(-2x)^5 = 6! / [5! (6-5)! ] * 3 * (-2)^5 x^5 = - 6*3*32 = - 576 x^5.
The coefficient of that term is - 576.
Answer: - 576
To get the correct answer to this question, you just need to divide 20% by 0.05% in order to get the answer, how many times a manual filer is more likely to make an error than an electronic file.
20: 0.05 = 400
The answer is C. 400 times more likely.
Complete Question:
The weather forecast for next season calls for a 10% chance of wind, a 20% chance of rain, a 30% chance of clouds, and a 40% chance of sunshine. If there are 90 days in the season,spin the spinner 90 times to simulate the 90-day weather forecast. Which type of weather has the lowest observed frequency?
Answer:
Wind Weather
Step-by-step explanation
From the question above
The sample space(which means the total number of events that we are considering ) = 90 times of spinning which represents the 90 days weather forecast
The chance of wind weather occurring is 10% and its observed frequency of occurrence within the 90 days is = 
= 9 days
The chance of rain weather occurring is 20% and its observed frequency of occurrence within the 90 days is = 
= 18 days
The chance of cloud weather occurring is 30% and its observed frequency of occurrence within the 90 days is = 
= 27 days
The chance of sunshine weather occurring is 40% and its observed frequency of occurrence within the 90 days is = 
= 36 days
We see from the above calculation that the weather with the lowest observed frequency is Wind weather
Answer:
Step-by-step explanation:
1)The probability of success in each of the 58 identical engine tests is p=0.92
n = 58
mean, u = np = 58×0.92 = 53.36
2) The only value that would be considered usual for this distribution is 91. This is because it is the only value between the minimum and maximum value
3) n = 546
p = 17/100 = 0.17
Mean = np = 546×0.17= 92.82
4) n = 1035
p = 36/100 = 0.36
np = 1035 × 0.36 = 372.6
5) The probability of success is 0.2.
p = 0.2
q= 1-p = 1-0.2 = 0.8
n = 35
standard deviation =
√npq = √35×0.2×0.8 = 2.34
6) p = 0.25
q = 1-0.25 = 0.75
n = 5
Variance = npq = 5×0.25×0.75 = 0.9
7) n = 982
p = 0.431
q = 1 - p = 1 - 0.431 = 0.569
Variance = npq = 982×0.431×0.569= 240.8
8) n = 500
p = 84/100 = 0.84
q = 1-0.84 = 0.16
Standard deviation = √npq
Standard deviation = √500×0.84×0.16 = 8.2
