Answer:
The correct answer is:
a. M54.6, C79.51, C80.1
Explanation:
- M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.
Malignant neoplasm of anus, unspecified
Neoplasm related pain (acute) (chronic)
Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
Malignant (primary) neoplasm, unspecified
- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.
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<span>The c++ operator delete is used to destroy dynamic variables.</span>
Answer:
Style sheet.
Explanation:
A website is a collection of web pages. Web development tools are mainly HTML,CSS and JavaScript. They have their individual functions in structuring a web page.
JavaScript is a purpose object oriented programming language widely used in web page for writing scripts, aimed to make web pages interactive.
HTML is a mark-up language which provides a non-linear structuring approach to web page development.
CSS or cascaded style sheet is a tool used to design the element and layout of web pages on a device screen.
Answer:
#include<iostream>
using namespace std;
void main()
{
int townA_pop,townB_pop,count_years=1;
double rateA,rateB;
cout<<"please enter the population of town A"<<endl;
cin>>townA_pop;
cout<<"please enter the population of town B"<<endl;
cin>>townB_pop;
cout<<"please enter the grothw rate of town A"<<endl;
cin>>rateA;
cout<<"please enter the grothw rate of town B"<<endl;
cin>>rateB;
while(townA_pop < townB_pop)//IF town A pop is equal or greater than town B it will break
{
townA_pop = townA_pop +( townA_pop * (rateA /100) );
townB_pop = townB_pop +( townB_pop * (rateB /100) );
count_years++;
}
cout<<"after "<<count_years<<" of years the pop of town A will be graeter than or equal To the pop of town B"<<endl;
}
Explanation:
