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Gala2k [10]
2 years ago
12

ABCD is a rectangle. Trapezoid AEFB is congruent to trapezoid CFED. G is the midpoint of segment EF. Select all the ways we coul

d describe the rigid transformation that takes AEFB to CFED .​

Mathematics
1 answer:
iris [78.8K]2 years ago
4 0

Answer: C, D and E

Step-by-step explanation: I'm a high school student and my teacher just went over this exact problem today. Here's somewhat how he explained it.

If you draw out trapezoid AEFB and turn it once clockwise or counterclockwise you would have only turned it 90 degrees but, turn it one more time (180) and you will see that it looks just like figure CFED. That's how I got the answers C and E. Ok, now for D its kinda the same thing Just because it say translate doesn't mean the shape would change. Even if you slide the shape and turn it two times in either direction you will still get figure CFED. Your Welcome

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Answer: $5,744.61

Step-by-step explanation:

year 1 = -2,277

year 2 = -2026.53

year 3 = -1803.61

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year 6 = -1271.49

year 7 = -1131.62

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A group of adults and students went on a class trip to Washington, DC. The number of male students was 1 more than 7 times the n
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X number of male students
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2 years ago
Complete the missing parts of the paragraph proof. Draw a perpendicular from P to AB. Label the intersection C. We are given tha
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<span>1) We are given that PA = PB, so PA ≅ PB by the definition of the radius.

</span>When you draw a perpendicular to a segment AB, you take the compass, point it at A and draw an arc of size AB, then you do the same pointing the compass on B. Point P will be one of the intersections of those two arcs. Therefore PA and PB correspond to the radii of the arcs, which were taken both equal to AB, therefore they are congruent. 
 
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Perpendicularity is the relation between two lines that meet at a right angle. Since we know that PC is perpendicular to AB by construction, ∠PCA and ∠PCB are right angles.
 
3) PC ≅ PC by the reflexive property congruence.

The reflexive property congruence states that any shape is congruent to itself.

4) So, triangle ACP is congruent to triangle BCP by HL, and AC ≅ BC by CPCTC (corresponding parts of congruent triangles are congruent). 

CPCTC states that if two triangles are congruent, then all of the corresponding sides and angles are congruent. Since ΔACP ≡ ΔBCP, then the corresponding sides AC and BC are congruent.
 
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<span>The perpendicular bisector of a segment is a line that cuts the segment into two equal parts (bisector) and that forms with the segment a right angle (perpendicular). Any point on the perpendicular bisector has the same distance from the segment's extremities. PC has exactly the characteristics of a perpendicular bisector of AB. </span>
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2 years ago
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Suppose that some country had an adult population of about 50 million, a labor-force participation rate of 60 percent, and an un
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People Unemployment =

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