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musickatia [10]
2 years ago
8

Which division problem does the diagram below best illustrate?

Mathematics
2 answers:
olganol [36]2 years ago
5 0
It would be the 2nd one 35 divide by 7=5
Katyanochek1 [597]2 years ago
3 0

Answer:

35 divided by 7=5.

Step-by-step explanation:

I took the quiz.

You might be interested in
Eden is cutting two triangular tiles for her bathroom. She needs the tiles to be congruent but is not sure she is cutting them t
Elis [28]

Answer:

I think its BC and FD

4 0
2 years ago
Read 2 more answers
1. The number of employees at a certain company is 1440 and is increasing
adelina 88 [10]

Answer:

y = 1440 e^{0.015 t}

y(9) = 1440 e^{0.015*9}= 1648.133

So then after 9 years we will have approximately 1649 number of employees

Step-by-step explanation:

For this case we want to model the number of employees and we need to use an exponential model given by this general expression:

y = y_o e^{rt}

For this case the initial amount is y_o = 1440 and the rate r =0.015

And then the model would be given by

y = 1440 e^{0.015 t}

And if we find the value for t =9 years we got:

y(9) = 1440 e^{0.015*9}= 1648.133

So then after 9 years we will have approximately 1649 number of employees

6 0
2 years ago
Find the values of x for which f(x)=g(x).<br><br> a. f(x) = x^2, g(x) = x + 2
quester [9]
One answer could be 2 as 2^2 is 4 and 2+2 also equals 4
4 0
2 years ago
A rectangular storage container with an open top is to have a volume of 10m3. Thelength of its base is twice the width. Material
frutty [35]

Answer:

$163.54

Step-by-step explanation:

Volume of rectangular container = 10m^3

Length = 2(width)

Material for the base cost $10 per square meter

Material for the side cost $6 per square meter

Volume = L*B*H

L= 2W

V = (2W).W. H

10 = 2W^2.H

H = 10 /2W^2

H = 5/W^2

Let C(w) = cost function

C(w) = 10(L.W) + 6(2.L.H + 2.W.H)

= 10(2W.W) + 6(2.2W.H + 2.W.H)

= 10(2W^2) + 6(4W.H + 2.W.H)

= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)

= 20W^2 + 6(20/W + 10/W)

= 20W^2 + 6((10+20)/W)

= 20W^2 + 6(30/W)

C(w) = 20W^2 + 180/W

To find the minimum value, differentiate C with respect to w

C'(w) = 40W - 180/W^2

Put C'(w) = 0

0 = 40W - 180/W^2

40W = 180/W^2

40W^3 = 180

W^3 = 180/40

W^3 = 4.5

W = cube rt(4.5)

W = 1.65m

C = 20(1.65)^2 + 180/1.65

C = 54.45 + 109.09

C= $163.54

Minimum cost = $163.54

6 0
2 years ago
Please help!!
rusak2 [61]
ANSWER TO QUESTION 1

The set of natural numbers that are factors of 20 are natural numbers that divides 20 exactly without a remainder.

These natural numbers are;

{1,2,4,5,10,20}

Therefore the correct answer is D

ANSWER TO QUESTION 2

Given that the universal set U has elements

{1,2,3,4,5,6,7,8,9,10}

and the set P also has elements

{2,4,6,8,10}

The elements of P' are the elements that are in the universal set but are not in set P.

These elements are;

{1,3,5,7,9}

The correct answer is C

ANSWER TO QUESTION 3

The distance is given by the absolute value equation

d=|130-25t|

If the is 15 feet away then d=15

This implies that;

15=|130-25t|

We now split the absolute value sign to obtain,

15=130-25t

or

-15=130-25t

We now solve for t to obtain;

15-130=-25t

or

-15-130=-25t

\frac{115}{25}=t

or

\frac{145}{25}=t

This gives us

4.6=t

or

5.8=t

The correct answer is C

ANSWER TO QUESTION 4

Given

P={0,1,2,3,4,56,7,8,9}

and

V={2,4,6,810,1216,18,20}

P\capV={2,4,6,8}

P\V are  elements in P only .

This means that we have to take out the elements of the intersection of the two sets from P.

P\V ={0,1,3,5,5,7,9}

The correct answer is B

ANSWER TO QUESTION 5

The correct answer is B.

In listing the elements of a set, we do not repeat the element. In order words we list only distinct elements.


Blueberry is repeating in both sets but we have to list it once.

ANSWER TO QUESTION 6.

The correct answer is 220

We were told that 250 play basket ball

If 120 play both sports, then

250-120=130

play only basketball

Now the number of people who play only baseball

350-250=100

But the number of people who play baseball

120+100=220

see diagram

7 0
2 years ago
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