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2 years ago

the Baker at a pizzeria divides a 6-pound batch of pizza dough into 16 equal-size balls. What is the weight of each dough ball?

Mathematics

2 answers:

trapecia [35]2 years ago

8 0

The weight of each dough ball is 0.375 ounces.

dangina [55]2 years ago

5 0

The weight of each dough ball is 6 oz because there is 16 oz in a pound.
16 x 6 = 96 oz in the batch of pizza dough.
96 divided by 16 is 6.
Therefore, there is 6 oz in each dough ball.

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Scilla [17]

$-15a^{2}b^{2}$

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2 years ago

Use the formula t=ln2/k that gives the time for a population, with a growth rate k, to double, to answer the following question.

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Answer:

k = 0.005
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Step-by-step explanation:

Matching the form

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we can identify the value of k as being 0.005.

k = 0.005

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The doubling time is given by the formula ...

t = ln(2)/k = ln(2)/0.005 ≈ 138.63

It will take about 139 years for the population to double.

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A bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than One-fifth? Select thr

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Answer:

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Step-by-step explanation:

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2 years ago

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A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr

guajiro [1.7K]

Step 1

Find the Volume of the two balls

we know that

the Volume of a sphere is equal to

$V=\frac{4}{3} \pi r^{3}$

In this problem we have

$r=1.5\ in$

Substitute

$V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}$

the volume of the two balls is equal

$V=2*4.5\pi=9 \pi\ in^{3}$

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to

$V=\pi r^{2}h$

In this problem we have

$r=1.5\ in$

$h=4*r=4*1.5=6\ in$

Substitute

$V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}$

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

$13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}$

Step 4

Find the volume of the square prism

The volume of the prism is equal to

$V=Bh$

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

$B=(2*1.5)^{2}=9\ in^{2}$ -----> the base is equal to the diameter

$h=4*r=4*1.5=6\ in$

Substitute

$V=9*6=54\ in^{3}$

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

$54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}$

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is $14.14\ in^{3}$

the amount of wasted space in the prism is $25.73\ in^{3}$

Find the difference

$25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}$

The package that has the least amount of wasted space is the cylinder

therefore

the answer is the option

the cylinder because it has approximately 11.6 in.3 less wasted space than the prism

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2 years ago

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