Use rounding to estimate the product. Is your estimate an underestimate or an overestimate? 8 × 9.82

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

dangina [55]

If one is to choose among given choices and the order is not important, we use the concept of combination. First, we calculate for the sample space or number available since there is a total number of 12 electives and a student may choose 2 out of them.
S = 12C2
That is "the sample space is equal to combination of 12 taken 2". The answer to this is equal to 66.

Next, we determine the number of outcomes. The equation will be,
O = (5C1) x (3C1)
That is "outcome is equal to combination of 5 taken 1 times combination of 3 taken 1". This is equal to 15. The probability is equal to,
P = O/S

Substituting,
P = (15/66) = 0.227270
The answer to this item is the third choice.

6 0

1 year ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Tanzania [10]

Answer:

Approximately, 159 men weighs more than 165 pounds and 159 men weighs less than 135 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 150 pounds

Standard Deviation, σ = 15

We are given that the distribution of weights of 1000 men is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P( men weighing more than 165 pounds)

P(x > 165)

$P( x > 165) = P( z > \displaystyle\frac{165 - 150}{15}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 165) = 1 - 0.8413 = 0.1587 = 15.87\%$

Approximately, 159 men weighs more than 165 pounds.

P(men weighing less than 135 pounds)

P(x < 135)

$P( x < 135) = P( z < \displaystyle\frac{135 - 150}{15}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 135) = 0.1587 = 15.87\%$

Approximately, 159 men weighs less than 135 pounds.

6 0

2 years ago

If m< LMP is 11 degrees more than m< NMP and m< NML =137, find each measure

Agata [3.3K]

First, note that for angles LMP and NMP you have

$m\angle LMP+m\angle NMP=m\angle NML.$

If $m\angle LMP$ is $11^{\circ}$ more than $m\angle MNP,$ then

$m\angle LMP=m\angle NMP+11^{\circ}.$

Now, since $m\angle MNL=137^{\circ},$ you have

$137^{\circ}=m\angle NMP+11^{\circ}+m\angle NMP,\\ \\2m\angle NMP=137^{\circ}-11^{\circ}=126^{\circ},\\ \\m\angle NMP=63^{\circ}.$

Therefore,

$m\angle LMP=63^{\circ}+11^{\circ}=74^{\circ}.$

Answer: $m\angle LMP=74^{\circ},\ m\angle NMP=63^{\circ}.$

7 0

2 years ago

On a coordinate plane, a curved line with a minimum value of (negative 1.25, negative 3.25) and a maximum value of (0.25, negati

Talja [164]

Answer: c

Step-by-step explanation:

its c.

8 0

1 year ago

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A merchant travels with 269 pounds of silver goods, 167 pounds of fruit, and 51 pounds of herbs, but only has 11 camels to carry

AURORKA [14]

Answer: The number of pounds each camel have to carry=44 pounds

The pounds of goods left=3 pounds

Step-by-step explanation:

The total pounds of goods the merchant have= $269+167+51$

=487 pounds

The total number of camels the merchant have = 11

If each camel carry same weight of goods, then we divide total weight by 11, we get

487÷11=44.27

The number of pounds each camel have to carry=44 pounds

The pounds of goods left=487-44×11=487-484=3 pounds

7 0

2 years ago