Answer:
Option 4 is correct.
The equation 
is equivalent to 
Step-by-step explanation:'
Given equation:
First group the terms with x and those with y;
Next, we complete the squares.
We can do this by adding a third term such that the x terms and the y terms are perfect squares.
For this we must either add the same value on the other side of the equation or subtract the same value on the same side so that the equality is maintained.
⇒
or
Add 360 on both sides we get;
Simplify:
Therefore, the given equation is equivalent to
So,
1. Type I profits $20
2. Type II profits $30
3. Type III profits $40
4. I/day < 100
5. Type I needs 5 hrs.
6. Type II needs 10 hrs.
7. Type III needs 15 hrs.
8. Total hrs. available: 2000 hrs.
Every +5 hrs. spent yields an extra $10.
If we use 500 hrs. to make 100 Type I stereos, we will profit $2000.
If we use 500 hrs. to make 50 Type II stereos, we will profit $1500.
If we use 495 hrs. to make 33 Type III stereos, we will profit $1320.
We should use the first 500 hrs. to make Type I stereos.
We should use the last 1500 hrs. to make Type II stereos.
$2000 + $4500 = x
$6500 = x
There must be 100 Type I stereos made along with 150 Type II stereos made.
Let the score of cowboys is x
and giants make score 9 which is twice less than the cowboys score so
giants score will be = 2x -9
and packers scored 14 more than giants that is (2x - 9) + 14
now sum of their scores is equal to 81 it means:
x + (2x - 9) + (2x -9) + 14 = 81
x + 2x - 9 + 2x - 9 + 14 = 81
5x = 81 + 4
5x = 85
x = 17
packers scored = (2x - 9) + 14
= 2 (17) -9 + 14
=38 + 5 = 43 points
Answer:
C) Linear
Step-by-step explanation:
We can see from the plot that the data approach a straight line.
This means we can draw a line of best fit through this data and it should hit several data points; thus the answer is linear.
Answer:
Step-by-step explanation:
Let the actual width of belt be x
we are given that the ideal width of safety belt strap is 5 cm
So, Difference between actual and ideal = (x-5)cm
We are also given that An actual width can vary by at most 0.35 cm.
So, The difference between actual and ideal width should be less than or equal to 0.35 cm
So, 
We know
and 
and 
and 
So,
Hence the range of acceptable widths is
