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salantis [7]
2 years ago
15

A hiker tries to prepare a hard-boiled egg on the high slopes of Mount Everest. The base camp is located 5,300 meters above sea

level. The hiker observes that the water begins to boil at 82⁰C, much lower than the 100⁰C needed to cook the raw egg. He hopes that just leaving the egg in the boiling water longer will let the egg cook. Will he have hard-boiled eggs for breakfast?
Chemistry
1 answer:
navik [9.2K]2 years ago
6 0

Answer:

He will not have hard-boiled eggs for breakfast

Explanation:

The given parameters are;

The elevation at which the base camp of the hiker is located = 5,300 meters

The boiling point of water at the elevation of the base camp = 82°C

The temperature required to cook the raw egg = 100°C

Therefore, we have;

The temperature of the boiling water at the given elevation of the base camp 82°C < The temperature required to cook the raw egg 100°C

Therefore, the eggs will not be hard boiled.

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Website
vredina [299]

Answer:

volume in L = 0.25 L

Explanation:

Given data:

Mass of Cu(NO₃)₂ = 2.43 g

Volume of KI = ?

Solution:

Balanced chemical equation:

2Cu(NO₃)₂  + 4KI    →    2CuI + I₂ + 4KNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 2.43 g/ 187.56 g/mol

Number of moles = 0.013 mol

Now we will compare the moles of Cu(NO₃)₂ with KI.

                        Cu(NO₃)₂       :              KI    

                              2              :               4

                            0.013          :            4 × 0.013=0.052 mol

Volume of KI:

<em>Molarity = moles of solute / volume in L</em>

volume in L = moles of solute /Molarity

volume in L =  0.052 mol / 0.209 mol/L

volume in L = 0.25 L

6 0
2 years ago
Q1) A vapor-compression refrigeration system operates on the cycle of Fig. 9.1. The refrigerant is 1,1,1,2-Tetrafluoroethane. Gi
hoa [83]

Answer:

i)   0.5071 (kg/s)

ii)  -1407.1 kj/kg

iii)  204.05 Kw

iv)  5.881

v)    9.238

Explanation:

Given Data:

evaporation temperature ( T ) = 4°c = 277.15 K

Condensation Temperature ( T ) = 34°c = 307.15 K

<em>n</em> ( compressor efficiency ) = 0.76

refrigeration rate = 1200 kJ.s^-1

i) determine the circulation rate of the refrigerant

m = \frac{Q}{H2 - H1}  = \frac{Q}{H2 - H4\\}  ------- 1

Q = 1200 Kj.s^-1

H2 = entropy at step 2 = 2508.9 (kJ / kg ) ( gotten from Table F )

H4 = entropy at step 4 = 142.4 ( kJ/ kg )

back to equation 1

m ( circulation rate of refrigerant ) = 0.5071 (kg/s)

ii) heat transfer rate in the condenser

Q = m ( H4 - H3 )

    = 0.5071 ( 142.4 - 2911.27 )

    = -1407.1 kj/kg

where H3 = H2 + ΔH23 = 2911.27 (kj/kg) ( as calculated )

iii) power requirement

w = m * ΔH23

   = 0.5071 (kg/s) * 402.37 (kj/kg) =  204.05 Kw

where: ΔH23 = \frac{H'3 - H2 }{0.76} = \frac{2814.7-2508.9}{0.76} = 402.37 (kj/kg)

iv) coefficient of performance of a cycle

W = Qc / w

  = 1200 Kj.s^-1/ 204.05 kw

  = 5.881

v) coefficient of performance of a Carnot refrigeration cycle

w_{carnot} = \frac{T2}{T4 - T2}

            =  277.15 / ( 307.15 - 277.15 )

            = 9.238

4 0
2 years ago
2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?
otez555 [7]

Answer:

100g/mol

Explanation:

Given parameters:

Mass of unknown gas  = 2g

Volume of gas in flask  = 500mL  = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;  

        1 mole of substance occupies 22.4dm³ of space at STP

    Therefore,

            0.5dm³ will have  0.02mole at STP

                     

Now;

   Number of moles  = \frac{mass}{molar mass}  

      Molar mass  = \frac{mass}{number of moles}   = \frac{2}{0.02}   = 100g/mol

4 0
2 years ago
A turtle moves at a speed of 1.0km/h. How fast is the turtle moving in meter per second (m/s)?
ahrayia [7]

Answer:

0.28m/s

Explanation:

Speed is defined as the distance travelled per unit of time. The speed of the turtle is 1.0km/h. Thus, to find the speed in m/s, we need to convert km to m (1km is 1000m), and h to s (1h = 3600s).

<em>Converting units:</em>

1.0km/h * (1000m / 1km) * (1h / 3600s) = 0.28m/s.

The speed of the turtle in meter per second is 0.28m/s

7 0
2 years ago
the hydrogen gas generated when calcium metal reacts with water is collected over water at 20 degrees C. The volume of the gas i
Gala2k [10]

Answer:

There is 0.0677 grams of H2 gas obtained

Explanation:

Step 1: Data given

The total pressure (988 mmHg) is the sum of the pressure of the collected hydrogen + the vapor pressure of water (17.54 mmHg).  

ptotal = p(H2)+ p(H2O)

p(H2) = ptotal - pH2O = 988 mmHg - 17.54 mmHg = 970.46 mmHg

Step 2: Calculate moles of H2 gas

Use the ideal gas law to calculate the moles of H2 gas

PV = nRT

n = PV / RT

 ⇒ with p = pressure of H2 in atm = 970.46 mmHg * (1 atm /760 mmHg) = 1.277 atm

⇒ V = volume of H2 in L = 641 mL x (1 L / 1000 mL) = 0.641 L

⇒ n = the number of moles of H2 = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 20.0 °C = 293.15 Kelvin

n = (1.277)(0.641) / (0.08206)(298.15) = 0.0335 moles H2

Step 3: Calculate mass of H2

Mass of H2 = moles H2 ¨molar H2

0.0335 moles H2 * 2.02 g/mol H2  = 0.0677g H2

There is 0.0677 grams of H2 gas obtained

7 0
2 years ago
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