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pishuonlain [190]
2 years ago
5

Select all the equations that have the same solution as the equation 3x-12=24

Mathematics
2 answers:
inn [45]2 years ago
7 0

Answer:

Select all the equations that have the same solution as the equation 3x-12=24

Step-by-step explanation:

Guest1 year ago
0 0

15x-60=120

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One of the factors of the polynomial x3 − 5x2 is x + 3. What is the other factor?
blondinia [14]

Answer:

C. x² − 8x + 24 − 72/(x+3)

Step-by-step explanation:

See attached picture for long division method.

Logically, we know x³ − 5x² factors to x² (x − 5).  Since x + 3 isn't a factor, we know the remainder isn't 0.  So we can narrow the options down to A or C.

One way to find the remainder is through long division.  Or, since this is multiple choice, we multiply the options by x + 3 and see which one results in an answer of x³ − 5x².

(x + 3) (x² − 8x + 24 − 72/(x+3))

(x + 3) (x² − 8x + 24) − 72

x³ − 8x² + 24x + 3x² − 24x + 72 − 72

x³ − 5x²

6 0
2 years ago
1. The following are the number of hours that 10 police officers have spent being trained in how to handle encounters with peopl
dusya [7]

Answer:

Range = 16

Inter\ Quartile\ Range = 6.75

Variance = 20.44

Standard\ Deviation = 4.52

Step-by-step explanation:

Given

4, 17, 12, 9, 6, 10, 1, 5, 9, 3

Calculating the range;

Range = Highest - Lowest

From the given data;

Highest = 17 and Lowest = 1

Hence;

Range = 17 - 1

Range = 16

Calculating the Inter-quartile Range

Inter quartile range (IQR) is calculates as thus

IQR = Q_3 - Q_1

Where

Q3 = Upper Quartile and Q1 = Lower Quartile

<em />

<em>Start by arranging the data in ascending order</em>

1, 3, 4, 5, 6, 9, 9, 10, 12, 17

N = Number of data; N = 10

---------------------------------------------------------------------------------

Calculating Q3

Q_3 = \frac{3}{4}(N+1) th\ item

<em>Substitute 10 for N</em>

Q_3 = \frac{3}{4}(10+1) th\ item

Q_3 = \frac{3}{4}(11) th\ item

Q_3 = \frac{33}{4} th\ item

Q_3 = 8.25 th\ item

Express 8.25 as 8 + 0.25

Q_3 = (8 + 0.25) th\ item

Q_3 = 8th\ item + 0.25 th\ item

Express 0.25 as fraction

Q_3 = 8th\ item +\frac{1}{4} th\ item

Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)

From the arranged data;

8th\ item = 10 and 9th\ item = 12

Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)

Q_3 = 10 +\frac{1}{4} (12 - 10)

Q_3 = 10 +\frac{1}{4} (2)

Q_3 = 10 +0.5

Q_3 = 10.5

Calculating Q1

Q_1 = \frac{1}{4}(N+1) th\ item

<em>Substitute 10 for N</em>

Q_1 = \frac{1}{4}(10+1) th\ item

Q_1 = \frac{1}{4}(11) th\ item

Q_1 = \frac{11}{4} th\ item

Q_1 = 2.75 th\ item

Express 2.75 as 2 + 0.75

Q_1 = (2 + 0.75) th\ item

Q_1 = 2nd\ item + 0.75 th\ item

Express 0.75 as fraction

Q_1 = 2nd\ item +\frac{3}{4} th\ item

Q_1 = 2nd\ item +\frac{3}{4} (3rd\ item - 2nd\ item)

From the arranged data;

2nd\ item = 3 and 3rd\ item = 4

Q_1 = 3 +\frac{3}{4} (4 - 3)

Q_1 = 3 +\frac{3}{4} (1)

Q_1 = 3 +0.75

Q_1 = 3 .75

---------------------------------------------------------------------------------

Recall that

IQR = Q_3 - Q_1

IQR = 10.5 - 3.75

IQR = 6.75

Calculating Variance

Start by calculating the mean

Mean = \frac{1+3+4+5+6+9+9+10+12+17}{10}

Mean = \frac{76}{10}

Mean = 7.6

Subtract the mean from each data, then square the result

(1 - 7.6)^2 = (-6.6)^2 = 43.56

(3 - 7.6)^2 = (-4.6)^2 = 21.16

(4 - 7.6)^2 = (-3.6)^2 = 12.96

(5 - 7.6)^2 = (-2.6)^2 = 6.76

(6 - 7.6)^2 = (-1.6)^2 = 2.56

(9 - 7.6)^2 = (1.4)^2 = 1.96

(9 - 7.6)^2 = (1.4)^2 = 1.96

(10 - 7.6)^2 = (2.4)^2 = 5.76

(12 - 7.6)^2 = (4.4)^2 = 19.36

(17 - 7.6)^2 = (9.4)^2 = 88.36

Sum the result

43.56 + 21.16 + 12.96 + 6.76 + 2.56 + 1.96 + 1.96 + 5.76 + 19.36 + 88.36 = 204.4

Divide by number of observation;

Variance = \frac{204.4}{10}

Variance = 20.44

Calculating Standard Deviation (SD)

SD = \sqrt{Variance}

SD = \sqrt{20.44}

SD = 4.52 <em>(Approximated)</em>

4 0
2 years ago
Automobile repair costs continue to rise with the average cost now at $367 per repair (U.S. News &amp; World Report website, Jan
tino4ka555 [31]

Answer:

\mu = 367

\sigma = 88

a. What is the probability that the cost will be more than $450?

We are supposed to find P(x > 450)

Formula : z=\frac{x-\mu}{\sigma}

z=\frac{450-367}{88}

z=0.9431

Refer the z table :

P(z<0.9431)=0.8264

P(z> 0.9431)=1-P(z<0.9431)=1- 0.8264= 0.1736

Hence the probability that the cost will be more than $450 is 0.1736

b)What is the probability that the cost will be less than $250?

We are supposed to find P(x<250)

Formula : z=\frac{x-\mu}{\sigma}

z=\frac{250-367}{88}

z=-1.3295

Refer the z table :

P(z<-1.3295)=0.0934

Hence the probability that the cost will be less than $250 is 0.0934

c)What is the probability that the cost will be between $250 and $450?

P(250<z<450)=P(z<450)-P(z<250) = 0.8264 - 0.0934 =0.733

Hence the probability that the cost will be between $250 and $450 is 0.733

d)  If the cost for your car repair is in the lower 5% of automobile repair charges, what is your cost?

p = 0.05

refer the z table

z = -1.65

Formula : z=\frac{x-\mu}{\sigma}

-1.65=\frac{x-367}{88}

-1.65 \times 88=x-367

-145.2+367=x

221.8=x

Hence If the cost for your car repair is in the lower 5% of automobile repair charges, so, cost is $221.8

4 0
2 years ago
The physician orders 1500 flu injections. There were 300 shots given in September, 450 shots given in October, and 665 shots giv
GalinKa [24]

Answer:

94.33

Step-by-step explanation:

add up all numbers then input into a percentage calculator

7 0
2 years ago
Read 2 more answers
Find the product of 4 5\6 and 2 1\2. Express your answer in simplest form.
dexar [7]
The answer should be B.

3 0
2 years ago
Read 2 more answers
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