Answer:
y= - 1/2 (negative half) = -0.5
Step-by-step explanation:
−6y+3(12y)=20(y−1)+15
Multiply 3 and 12 to get 36.
−6y+36y=20(y−1)+15
Combine −6y and 36y to get 30y.
30y=20(y−1)+15
Use the distributive property to multiply 20 by y−1.
30y=20y−20+15
Add −20 and 15 to get −5.
30y=20y−5
Subtract 20y from both sides.
30y−20y=−5
Combine 30y and −20y to get 10y.
10y=−5
Divide both sides by 10
y= -5/10
Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .
Answer:
279,936 ways
Step-by-step explanation:
Every day the student has to chose a sandwich from the pile of 6 sandwiches. So this means the student has to make a choice from the 6 sandwiches for the 7 days. Since the order matters, this is a problem of permutations.
Daily the student has the option to chose from 6 sandwiches. So this means, for 7 days, he has to make a choice out of 6 options. Or in other words we can say, the student has to make selection from 6 objects 7 times.
So, the total number of ways to chose the sandwiches will be 6 x 6 x 6 x 6 x 6 x 6 x 6 = 
Alternate Method:
Since the repetition can occur in this case, i.e. a sandwich chosen on one day can also be chosen on other day, the following formula of permutations ca be used:
Number of ways = 
where n is the total number of choices available which is 6 in this case and r is the number of times the selection is to be made which 7 in this case. So,
The number of ways to chose a sandwich will be =
ways
Answer:
Step-by-step explanation:
Triangles by definition have 3 sides. If the sides are corresponding then it is beneficial to us if they are the same length as well. If all 3 sides in one triangle are equal in length to the corresponding sides in another triangle, then the triangles are congruent by SSS (side-side-side). This is the case for us. Side EC is corresponding and congruent to side AC; side CD is corresponding and congruent to side CB; side ED is corresponding and congruent to side AB.
Answer:
Plane A and QRV intersection line is QR.
Explanation:
The plane QRV contains the rectangle QRVN. This rectangle intersects the plane A in the line QR.
Plane A and QRV intersection line is QR.
If one knows a specific line in one plane (for example, two points in the plane), and this line intersects the other plane, then its point of intersection.
Thus, it is on the line of intersection for the two planes.
Point W because the line intersects the y axis at W (0,2). sorry if it’s wrong :/