Answer:
Small intestine, liver, bile and lipase.
Explanation:
Digestion of fat occurs in the small intestine. Its digestion occurs with the help of bile, that is made in the liver. Bile breaks the fat into small drops that are easier for the lipase enzymes to change it. Lipase enzymes is a type of enzymes that works only on lipids and lipids are broken down into fatty acids and glycerol. These substances are absorbed by our body and used it for producing ATP for the body.
The teacher would be well advised to help students encode information about the cell using both visual and verbal forms. This is because, multiple forms of encoding increases the probability of easy retrieval. Encoding in this case involves converting the names of the cell organelles to forms that can easily be remembered.
Answer:
The statement that is true about red currents in the thermohaline circulation is that water in the red currents contain less salt (option A).
Explanation:
Thermohaline circulation is a concept used in oceanography, referring to the oceanic circulation that depends on factors such as surface heat and salinity, as well as the density gradient that they determine.
On a map, the different currents that are part of the thermohaline circulation are usually represented with blue and red lines, where:
- <em>The blue lines represent deep, cold, dense and higher salinity currents.</em>
- <em>The red lines represent surface currents, warm, with less salt content, so they are less dense.</em>
The red currents (see image) represented on the map have less salt content, compared to the currents represented in blue.
Learn more:
Thermohaline circulation brainly.com/question/8369487
Answer:
Species diversity is concerned with both commonalities and differences. This is seen in the variety of species from mammals to insects. This shows the classifications of the species in the environment in order for them to survive and adopt to the changes and climate.
Explanation:
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
